从 Twitter 搜索 API 解析 trends.json

Question

正在努力解析来自 http://api.twitter.com/1/trends/ 的 JSON 响应current.json

使用 foreach ($json_output->trends[0] as $trend ) { echo $趋势->名称; }

stdClass Object ( [trends] => stdClass Object ( [2011-05-03 17:43:42] => Array ( [0] => stdClass Object ( [query] => TeAmamosLuanS [events] => [promoted_content] => [name] => TeAmamosLuanS ) [1] => stdClass Object ( [query] => CASEY RULES [events] => [promoted_content] => [name] => CASEY RULES ) [2] => stdClass Object ( [query] => Rashard Mendenhall [events] => [promoted_content] => [name] => Rashard Mendenhall ) [3] => stdClass Object ( [query] => Alexandre Nardoni [events] => [promoted_content] => [name] => Alexandre Nardoni ) [4] => stdClass Object ( [query] => Henrique Capriles [events] => [promoted_content] => [name] => Henrique Capriles ) [5] => stdClass Object ( [query] => LivroRestart [events] => [promoted_content] => [name] => LivroRestart ) [6] => stdClass Object ( [query] => TeamXtina [events] => [promoted_content] => [name] => TeamXtina ) [7] => stdClass Object ( [query] => Howard Webb [events] => [promoted_content] => [name] => Howard Webb ) [8] => stdClass Object ( [query] => Camp Nou [events] => [promoted_content] => [name] => Camp Nou ) [9] => stdClass Object ( [query] => MTV Movie Awards [events] => [promoted_content] => [name] => MTV Movie Awards ) ) ) [as_of] => 1304444622 ) 

请帮助数组/对象解析。谢谢。

Answer 1

你可以使用类似的东西：

<?php
$json_output = json_decode(file_get_contents("http://api.twitter.com/1/trends/current.json"));
foreach ($json_output->trends as $datetime=>$vals ) {
    echo "As of $datetime the trends are:<br />";
    echo "<ul>";
    foreach($vals as $trend)
        echo "<li>{$trend->name}</li>";
    echo "</ul>";
}
?>

输出：

截至2011-05-03 22:07:58 趋势
是：

• #onethingiveneverdone
• #开启
• #pssst
• 伊恩·布鲁
• 贾斯汀·比伯伦
• 可怜的梅西
• 德里克·罗斯 MVP
• 仙妮亚·唐恩
• 拉沙德·门登霍尔
• 拉丁语BeliebersASKDates