如果readystate = 4且status = 200则执行Jquery S.Ajax错误处理程序

发布于 2024-11-04 14:55:12 字数 3358 浏览 2 评论 0原文

我正在执行 $.ajax 调用,它返回 json 响应,一切看起来都很好,但不是调用成功处理程序,而是调用 $.ajax 错误处理程序,即使 readystate=4 和 status=200 也是如此。

$.ajax 调用是:-

    $.ajax({
        url: 'inc/ajax_printorder.asp',
        type: "GET",
        data: data,
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        cache: false,
        success: function (sendresponse) {
            var message = (typeof sendresponse.jsonresp) == 'string' ? eval('(' + sendresponse.jsonresp + ')') : sendresponse.jsonresp;
            if (message[0].ok == '1') {
                var order = window.open('', 'PrintWindow', 'width=600,height=600');
                var html = '<html><head><title>Print Your Order</title></head><body><div id="myprintorder">' + $('<div />').append(message[0].msg) + '</div></body></html>';
                order.document.open();
                order.document.write(html);
                order.document.close();
                return false;
            };
        },
        error: function (xhr, err) {
            alert("readyState: " + xhr.readyState + "\nstatus: " + xhr.status);
            alert("responseText: " + xhr.responseText);
        }
    });

从 Firebug 中,ajax 响应是:-

{"jsonresp":[{"__type":"sendresponse","ok":"1","msg":"<h1>Your www.sandwichlunchesnewbury.co.uk order on 02/05/2011 00:34:01</h1><p>Website order from www.sandwichlunchesnewbury.co.uk on 02/05/2011 00:34:01 from:- </p><table width="60%" style="border:1px solid blue;padding:5px;"><tr><td>Name</td><td> a </td></tr><tr><td>Phone</td><td> b </td></tr><tr><td>Email</td><td>  </td></tr><tr><td>Business name</td><td>  </td></tr><tr><td>Delivery address</td><td> c </td></tr><tr><td>Date food required</td><td> Monday, 02/05/2011 </td></tr><tr><td>Time food required</td><td> 10 Am </td></tr><tr><td>&nbsp;</td><td>&nbsp;</td></tr><tr><td>Just Sandwiches (standard)</td><td>  </td></tr><tr><td>Just Sandwiches (gourmet)</td><td>  </td></tr><tr><td>Just Baguettes (standard)</td><td>  </td></tr><tr><td>Just Baguettes (gourmet)</td><td>  </td></tr><tr><td>Gourmet Bread Sandwiches</td><td> 2 </td></tr><tr><td>Sausage rolls</td><td>  </td></tr><tr><td>Cookie boxes</td><td>  </td></tr><tr><td>&nbsp;</td><td>&nbsp;</td></tr><tr><td>Total price</td><td> &pound;50.00 </td></tr><tr><td>&nbsp;</td><td>&nbsp;</td></tr><tr><td colspan="2">Other info & special instructions </td></tr><tr><td colspan="2"> </td></tr></table>"}]}

关于为什么会出错而不是成功的任何想法?

谢谢艾克斯

I'm doing an $.ajax call, which is returning a json response and all seems fine, but instead of the success handler being invoked, the $.ajax error handler is invoked even though the readystate=4 and the status=200.

The $.ajax call is:-

    $.ajax({
        url: 'inc/ajax_printorder.asp',
        type: "GET",
        data: data,
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        cache: false,
        success: function (sendresponse) {
            var message = (typeof sendresponse.jsonresp) == 'string' ? eval('(' + sendresponse.jsonresp + ')') : sendresponse.jsonresp;
            if (message[0].ok == '1') {
                var order = window.open('', 'PrintWindow', 'width=600,height=600');
                var html = '<html><head><title>Print Your Order</title></head><body><div id="myprintorder">' + $('<div />').append(message[0].msg) + '</div></body></html>';
                order.document.open();
                order.document.write(html);
                order.document.close();
                return false;
            };
        },
        error: function (xhr, err) {
            alert("readyState: " + xhr.readyState + "\nstatus: " + xhr.status);
            alert("responseText: " + xhr.responseText);
        }
    });

and from Firebug, the ajax response is:-

{"jsonresp":[{"__type":"sendresponse","ok":"1","msg":"<h1>Your www.sandwichlunchesnewbury.co.uk order on 02/05/2011 00:34:01</h1><p>Website order from www.sandwichlunchesnewbury.co.uk on 02/05/2011 00:34:01 from:- </p><table width="60%" style="border:1px solid blue;padding:5px;"><tr><td>Name</td><td> a </td></tr><tr><td>Phone</td><td> b </td></tr><tr><td>Email</td><td>  </td></tr><tr><td>Business name</td><td>  </td></tr><tr><td>Delivery address</td><td> c </td></tr><tr><td>Date food required</td><td> Monday, 02/05/2011 </td></tr><tr><td>Time food required</td><td> 10 Am </td></tr><tr><td> </td><td> </td></tr><tr><td>Just Sandwiches (standard)</td><td>  </td></tr><tr><td>Just Sandwiches (gourmet)</td><td>  </td></tr><tr><td>Just Baguettes (standard)</td><td>  </td></tr><tr><td>Just Baguettes (gourmet)</td><td>  </td></tr><tr><td>Gourmet Bread Sandwiches</td><td> 2 </td></tr><tr><td>Sausage rolls</td><td>  </td></tr><tr><td>Cookie boxes</td><td>  </td></tr><tr><td> </td><td> </td></tr><tr><td>Total price</td><td> £50.00 </td></tr><tr><td> </td><td> </td></tr><tr><td colspan="2">Other info & special instructions </td></tr><tr><td colspan="2"> </td></tr></table>"}]}

Any thoughts on why its going to error rather than success?

Thanks

epx

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瞄了个咪的 2024-11-11 14:55:12

您的响应 JSON 无效,除其他外,您需要转义双引号(\" 而不是 ")。您没有发布错误文本(传递给 errorerr 值),但我怀疑它是 parsererror

我发现 JSONLint 对于确保接收/发送有效的 JSON 非常有用。

Your response JSON is invalid, among other things, you will need to escape the double quotes (\" instead of "). You didn't post what the error text (the value of err as passed to error) is but I suspect it'll be parsererror.

I've found JSONLint to be very useful in ensuring I'm receiving/sending valid JSON.

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