转换 C++类到 C 结构（及其他结构）

发布于 2024-11-04 11:24:01 字数 530 浏览 1 评论 0原文

这几天我一直在“降级”> 1000 filem C++ 代码转换为 C。到目前为止一切进展顺利。突然我和一个类面对面了...

编译器首先在头文件中指出了错误：

class foobar {
    foo mutex;
public:
    foobar() {
        oneCreate(&mutex, NULL);
    }
    ~foobar() {
        oneDestroy(mutex);
        mutex = NULL;
    }
    void ObtainControl() {
        oneAcquire(mutex);
    }
    void ReleaseControl() {
        oneRelease(mutex);
    }
};

当然，C文件必须利用这一点

foobar fooey;
fooey.ObtainControl();

我什至不知道从哪里开始... 。帮助？

原文

Past few days I have been "downgrading" > 1000 filem of C++ code into C.
It's been going well until now. Suddenly I'm face to face with a class...

The compiler pointed out the error first in the header file:

class foobar {
    foo mutex;
public:
    foobar() {
        oneCreate(&mutex, NULL);
    }
    ~foobar() {
        oneDestroy(mutex);
        mutex = NULL;
    }
    void ObtainControl() {
        oneAcquire(mutex);
    }
    void ReleaseControl() {
        oneRelease(mutex);
    }
};

And of course, the C file has to take advantage of this

foobar fooey;
fooey.ObtainControl();

I don't even know where to start.... Help?

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海螺姑娘 2024-11-11 11:24:02

由于 C 结构不能有成员函数，您可以创建函数指针，或创建这些函数的非成员版本，例如：

struct foobar {
    foo mutex;
};

Construct_foobar(foobar* fooey) {
    oneCreate(&fooey->mutex, NULL);
}
Destroy_foobar(foobar* fooey) {
    oneDestroy(fooey->mutex);
    fooey->mutex = NULL;
}
void ObtainControl(foobar* fooey) {
    oneAcquire(fooey->mutex);
}
void ReleaseControl(foobar* fooey) {
    oneRelease(fooey->mutex);
}

并在 .C 文件中：

foobar fooey;
construct_foobar( &fooey );
ObtainControl( &fooey );

since C-structs can't have member functions, you can either make function pointers, or create non-member versions of those functions, ex:

struct foobar {
    foo mutex;
};

Construct_foobar(foobar* fooey) {
    oneCreate(&fooey->mutex, NULL);
}
Destroy_foobar(foobar* fooey) {
    oneDestroy(fooey->mutex);
    fooey->mutex = NULL;
}
void ObtainControl(foobar* fooey) {
    oneAcquire(fooey->mutex);
}
void ReleaseControl(foobar* fooey) {
    oneRelease(fooey->mutex);
}

and in the .C file:

foobar fooey;
construct_foobar( &fooey );
ObtainControl( &fooey );

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九歌凝 2024-11-11 11:24:02

实际上有从 C++ 编译为 C 的编译器。不过，输出并不适合人类消化，请参阅如何将 C++ 代码转换为 C。

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笑叹一世浮沉 2024-11-11 11:24:02

这取决于您的编译器，因为 C 中没有 RAII 的标准方法。请参阅此问题并最佳答案。

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娇俏 2024-11-11 11:24:01

将 foobar 变成普通结构

struct foobar {
    goo mutex;
};

创建您自己的“构造函数”和“析构函数”作为您在该结构上调用的函数

void InitFoobar(foobar* foo)
{
   oneCreate(&foo->mutex);
}

void FreeFoobar(foobar* foo)
{
   oneDestroy(foo->mutex);
}

struct foobar fooStruct;
InitFoobar(&fooStruct);
// ..
FreeFoobar(&fooStruct);

等

Turn foobar into a normal struct

struct foobar {
    goo mutex;
};

Create your own "constructor" and "destructor" as functions that you call on that struct

void InitFoobar(foobar* foo)
{
   oneCreate(&foo->mutex);
}

void FreeFoobar(foobar* foo)
{
   oneDestroy(foo->mutex);
}

struct foobar fooStruct;
InitFoobar(&fooStruct);
// ..
FreeFoobar(&fooStruct);

etc

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