将 if 语句转换为 for 循环？

发布于 2024-11-04 09:49:41 字数 1677 浏览 0 评论 0原文

我在 mikroC 中编写了一个函数，用于扫描 4x4 键盘中按下的按键

void scan_key()
{
    PORTB = 0B11111110;
    if ( PORTB == 0b11101110){
        Row = 1;
        Column = 1;
        return;
    }
    if ( PORTB == 0b11011110){
        Row = 2;
        Column = 1;
        return;
    }
    if ( PORTB == 0b10111110){
        Row = 3;
        Column = 1;
        return;
    }
    if ( PORTB == 0b01111110){
        Row = 4;
        Column = 1;
        return;
    }

    PORTB = 0B11111101;
    if ( PORTB == 0b11101101){
        Row = 1;
        Column = 2;
        return;
    }
    if ( PORTB == 0b11011101){
        Row = 2;
        Column = 2;
        return;
    }
    if ( PORTB == 0b10111101){
        Row = 3;
        Column = 2;
        return;
    }
    if ( PORTB == 0b01111101){
        Row = 4;
        Column = 2;
        return;
    }

    PORTB = 0B11111011;
    if ( PORTB == 0b11101011){
        Row = 1;
        Column = 3;
        return;
    }
    if ( PORTB == 0b11011011){
        Row = 2;
        Column = 3;
        return;
    }
    if ( PORTB == 0b10111011){
        Row = 3;
        Column = 3;
        return;
    }
    if ( PORTB == 0b01111011){
        Row = 4;
        Column = 3;
        return;
    }

    PORTB = 0B11110111;
    if ( PORTB == 0b11100111){
        Row = 1;
        Column = 4;
        return;
    }
    if ( PORTB == 0b11010111){
        Row = 2;
        Column = 4;
        return;
    }
    if ( PORTB == 0b10110111){
        Row = 3;
        Column = 4;
        return;
    }
    if ( PORTB == 0b01110111){
        Row = 4;
        Column = 4;
        return;
    }

    PORTB = 0B11110000;
}

有没有办法将此算法转换为循环？

原文

I've written a function in mikroC that scan the pressed key in a 4x4 keypad

void scan_key()
{
    PORTB = 0B11111110;
    if ( PORTB == 0b11101110){
        Row = 1;
        Column = 1;
        return;
    }
    if ( PORTB == 0b11011110){
        Row = 2;
        Column = 1;
        return;
    }
    if ( PORTB == 0b10111110){
        Row = 3;
        Column = 1;
        return;
    }
    if ( PORTB == 0b01111110){
        Row = 4;
        Column = 1;
        return;
    }

    PORTB = 0B11111101;
    if ( PORTB == 0b11101101){
        Row = 1;
        Column = 2;
        return;
    }
    if ( PORTB == 0b11011101){
        Row = 2;
        Column = 2;
        return;
    }
    if ( PORTB == 0b10111101){
        Row = 3;
        Column = 2;
        return;
    }
    if ( PORTB == 0b01111101){
        Row = 4;
        Column = 2;
        return;
    }

    PORTB = 0B11111011;
    if ( PORTB == 0b11101011){
        Row = 1;
        Column = 3;
        return;
    }
    if ( PORTB == 0b11011011){
        Row = 2;
        Column = 3;
        return;
    }
    if ( PORTB == 0b10111011){
        Row = 3;
        Column = 3;
        return;
    }
    if ( PORTB == 0b01111011){
        Row = 4;
        Column = 3;
        return;
    }

    PORTB = 0B11110111;
    if ( PORTB == 0b11100111){
        Row = 1;
        Column = 4;
        return;
    }
    if ( PORTB == 0b11010111){
        Row = 2;
        Column = 4;
        return;
    }
    if ( PORTB == 0b10110111){
        Row = 3;
        Column = 4;
        return;
    }
    if ( PORTB == 0b01110111){
        Row = 4;
        Column = 4;
        return;
    }

    PORTB = 0B11110000;
}

Is there a way to convert this algorithm into a loop?

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北凤男飞 2024-11-11 09:49:41

是的。（至少假设您实际上并不打算在每个 if 块之前进行这些分配。我假设它们是为了测试？否则您的代码就没有意义。）

至少，您可以将每个二进制值放入一个数组中，并构造一个如下所示的循环：

int portValue[4][4] = {{0b11101110, 0b11011110, 0b10111110, 0b01111110}, {//...Rest of values here }}

int loop_col = 0;
int loop_row = 0;

for (loop_col = 0; loop_col < 4; loop_col++){
    for (loop_row = 0; loop_row < 4; loop_row++){
         if ( PORTB == portValue[loop_col][loop_row]){
             Row = loop_row + 1;
             Column = loop_col + 1;
             return;
         }
    }
}

Yes. (At least assuming you don't actually mean to have those assignments before each block of ifs. I assume they were there for testing? otherwise your code doesn't make sense.)

At the very least, you can put each of the binary values into an array, and construct a loop like this:

int portValue[4][4] = {{0b11101110, 0b11011110, 0b10111110, 0b01111110}, {//...Rest of values here }}

int loop_col = 0;
int loop_row = 0;

for (loop_col = 0; loop_col < 4; loop_col++){
    for (loop_row = 0; loop_row < 4; loop_row++){
         if ( PORTB == portValue[loop_col][loop_row]){
             Row = loop_row + 1;
             Column = loop_col + 1;
             return;
         }
    }
}

回复收藏 0 原文

金兰素衣 2024-11-11 09:49:41

是的当然。

首先用你的值做一些数组。
我们称之为 t[]
第二个是 d[][] // 二维数组

，让我们做双循环

for(i=1;i<=4;i++)
{
    cur_value=t[i]; // our value

    for(j=1;j<=4;j++)
    {
        right_side_value=d[i][j];
        if(cur_value==right_side_value)
        {
            rows=i;
            columns=j;
            return;
        }
    }
}

希望有帮助。

不知道一维数组是否只需要 d 值，没有检查每个数字

Yes of course.

First do some array with your values.
we'll call it t[]
and second is d[][] // two dimensional array

and lets do double loop

for(i=1;i<=4;i++)
{
    cur_value=t[i]; // our value

    for(j=1;j<=4;j++)
    {
        right_side_value=d[i][j];
        if(cur_value==right_side_value)
        {
            rows=i;
            columns=j;
            return;
        }
    }
}

Hope that helps.

Don't know if 1 dimensional array is only needed for d values, didnt check every number

回复收藏 0 原文

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