axis2客户端NTLM身份验证

Question

我有一个 axis2 (v1.5.3) 客户端，需要使用 IIS 进行 Kerberos/NTLM 身份验证。我该怎么做？这是我现在拥有的代码，它失败并出现 401 - 未经授权 错误：

List<String> authScheme = new ArrayList<String>();
authScheme.add(HttpTransportProperties.Authenticator.NTLM);
HttpTransportProperties.Authenticator ntlm =
                 new HttpTransportProperties.Authenticator();
ntlm.setAuthSchemes(authScheme);
ntlm.setUsername("Administrator");
ntlm.setPassword("password");
ntlm.setHost("http://server/_vti_bin/someservice.asmx");
ntlm.setPort(80);
ntlm.setDomain("server_domain");
Options options = webs._getServiceClient().getOptions();
options.setProperty(HTTPConstants.AUTHENTICATE, ntlm);
stub._getServiceClient().setOptions(options);  

用 C# 编写的客户端可以在相同的身份验证设置下正常工作：

CredentialCache myCache = new CredentialCache();            
myCache.Add(new Uri(webs.Url), "NTLM", 
            new NetworkCredential("Administrator", "password", "server_domain"));
stub.Credentials = myCache;

Answer 1

AXIS2 中的 NTLM 存在问题。它以 ntlm.setHost() 方法为中心。此处的条目既用作 NTLM 交换中的工作站，也用作创建 AuthScope 时的远程主机。这会造成第 22 条军规 (Catch-22) 情况，其中 NTLM 无法使用 HttpTransportProperties.Authenticator 技术工作。您要么收到“401 未经授权”，要么收到“未找到@HOST 的凭据”。

请参阅https://issues.apache.org/jira/browse/AXIS2-4595

彼得

Answer 2

HttpClient 不支持 NTLM v2，因此我使用 JCIFS 库返回 NTLM v1,2,3 消息类型，如本网站所述

http://devsac.blogspot.com/2010/10/supoprt-for-ntlmv2-with-apache.html

我刚刚使用了 JCIFS_NTLMScheme.java 文件在上面的网站上注册身份验证方案并且它有效！！！

示例客户端：

List authSchema = new ArrayList();
AuthPolicy.registerAuthScheme(AuthPolicy.NTLM, org.tempuri.JCIFS_NTLMScheme.class);
HttpTransportProperties.Authenticator auth = new HttpTransportProperties.Authenticator();
auth.setUsername("");
auth.setPassword("");
auth.setDomain("");
auth.setHost("");
auth.setPort();
List authPrefs = new ArrayList(1);
authPrefs.add(AuthPolicy.NTLM);
auth.setAuthSchemes(authPrefs);
stub._getServiceClient().getOptions().setProperty(org.apache.axis2.transport.http.HTTPConstants.AUTHENTICATE, auth); 

Answer 3

根据此链接中的注释Axis2 的 NTLM 问题

Axis2 仍然使用旧的 HTTPClient 库，并且该版本似乎不支持 NTLM 的所有版本（v1、v2）。而且将传输切换到 HTTPClient v4.1 也并非易事

我放弃了 Axis2 并使用 CXF 代替。

以下链接确实帮助我们解决了 Kerboros/NTLM 问题

http://download.oracle.com/javase/6/docs/technotes/guides/net/http-auth.html

Answer 4

JCIFS 的替代方法是使用 Apache HTTPComponents 4 NTLMScheme（它与新的NTLM）位于自定义 Apache Commons HTTP AuthScheme 中：

public class BackportedNTLMScheme extends org.apache.http.impl.auth.NTLMScheme implements org.apache.commons.httpclient.auth.AuthScheme {

    @Override
    public String authenticate(final Credentials credentials, final HttpMethod method) throws AuthenticationException {
        org.apache.commons.httpclient.NTCredentials oldCredentials;
        try {
            oldCredentials = (org.apache.commons.httpclient.NTCredentials) credentials;
        } catch (final ClassCastException e) {
            throw new InvalidCredentialsException(
                    "Credentials cannot be used for NTLM authentication: " 
                    + credentials.getClass().getName());
        }
        final org.apache.http.auth.Credentials adaptedCredentials = new NTCredentials(oldCredentials.getUserName(), oldCredentials.getPassword(), oldCredentials.getHost(), oldCredentials.getDomain());

        try {
            final Header header = super.authenticate(adaptedCredentials, null);
            return header.getValue();
        } catch (final org.apache.http.auth.AuthenticationException e) {
            throw new AuthenticationException("AuthenticationException", e);
        }
    }

    @Override
    public void processChallenge(final String challenge) throws MalformedChallengeException {
        final String s = AuthChallengeParser.extractScheme(challenge);
        if (!s.equalsIgnoreCase(getSchemeName())) {
            throw new MalformedChallengeException("Invalid NTLM challenge: " + challenge);
        }
        int challengeIdx = challenge.indexOf(' ');
        final CharArrayBuffer challengeBuffer;
        if(challengeIdx != -1){
            challengeBuffer = new CharArrayBuffer(challenge.length());
            challengeBuffer.append(challenge);
        } else {
            challengeBuffer = new CharArrayBuffer(0);
            challengeIdx = 0;
        }
        try {
            parseChallenge(challengeBuffer, challengeIdx, challengeBuffer.length());
        } catch (final org.apache.http.auth.MalformedChallengeException e) {
            throw new MalformedChallengeException("MalformedChallengeException", e);
        }
    }

    @Override
    @Deprecated
    public String getID() {
        throw new RuntimeException("deprecated vc.bjn.catalyst.forecast.BackportedNTLMScheme.getID()");
    }


    @Override
    @Deprecated
    public String authenticate(final Credentials credentials, final String method, final String uri) throws AuthenticationException {
        throw new RuntimeException("deprecated vc.bjn.catalyst.forecast.BackportedNTLMScheme.authenticate(Credentials, String, String)");
    }
}

用法

AuthPolicy.registerAuthScheme(AuthPolicy.NTLM, BackportedNTLMScheme.class);

我在 Windows Server 2008 R2 上的 IIS 7.5 上对此进行了测试。