Python、numpy、矩阵

发布于 2024-11-04 07:21:19 字数 360 浏览 1 评论 0原文

A=[['2' '7' 'fas']
 ['4' '8' 'sda']
 ['1' '5' 'daf']
 ['2' '24' 'gag']]

我怎样才能得到矩阵A，而不是每行中的最后一个“属性”：

A=[['2' '7']
 ['4' '8']
 ['1' '5' ]
 ['2' '24']]

我知道行中的最后一个元素是[：-1]

我尝试使用numpy：

A[:,  ?? ]

矩阵A是随机元素，所以我在想一些东西这样：A[:,end-1]，但numpy不知道什么是end

原文

A=[['2' '7' 'fas']
 ['4' '8' 'sda']
 ['1' '5' 'daf']
 ['2' '24' 'gag']]

How can I get just matrix A, instead last "atribute" in each row:

A=[['2' '7']
 ['4' '8']
 ['1' '5' ]
 ['2' '24']]

I know that last element in row is [:-1]

I tried with numpy:

A[:,  ?? ]

Matrix A is random elements, so I was thinking somethin in this way: A[:,end-1], but numpy don't know what is end

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无所谓啦 2024-11-11 07:21:19

>>> arr=np.array([[1,2,3],[4,5,6],[7,8,9]])
>>> arr[:,:-1]
array([[1, 2],
       [4, 5],
       [7, 8]])

>>> arr=np.array([[1,2,3],[4,5,6],[7,8,9]])
>>> arr[:,:-1]
array([[1, 2],
       [4, 5],
       [7, 8]])

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谁对谁错谁最难过 2024-11-11 07:21:19

>>> A = [ ['2', '7', 'fas']
        , ['4', '8', 'sda']
        , ['1', '5', 'daf']
        , ['2', '24', 'gag']
        ]

>>> [ x[:-1] for x in A ]
[['2', '7'], ['4', '8'], ['1', '5'], ['2', '24']]

>>> A = [ ['2', '7', 'fas']
        , ['4', '8', 'sda']
        , ['1', '5', 'daf']
        , ['2', '24', 'gag']
        ]

>>> [ x[:-1] for x in A ]
[['2', '7'], ['4', '8'], ['1', '5'], ['2', '24']]

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