需要 Expect/ExpectJ 专家的帮助

Question

可以说我有以下 shellscript details.sh

echo "name"
read name
if [ "$name" == "abcd" ]; then
echo "hi"
echo "hello"
echo "bye"
fi

=================================== ============

这是我的 Java 代码

ExpectJ exp = new ExpectJ();
String cmd = "sh details.sh"; //Command for execution of **details.sh**
Spawn s = exp.spawn(cmd); //Spawns the process **details.sh**
s.expect("name");  //Expecting "name" from the script
s.send("abcd");  //When successful, it sends **abcd** as the input to the script

//Now the script will compare the input(given by java code) with the pre-fed one (the one in the script)

s.expect("hi");  //according to me only **hi** must be displayed,but the java console is taking and displaying all the consecutive echo statements from the script.

知道为什么会发生这种情况吗？或者它应该只是这样表现吗？

Answer 1

看看你的脚本输出，我会输入以下期望

s.expect("hi\nhello\nbye");

Answer 2

好吧，即使你只有其中之一，它也会显示相同的字符串。它显示所有连续的字符串。我了解到这是 expectj.Spawn.expect() 的自然行为。这就是它的工作原理。

在这种情况下，即使我 put-

s.expect("hi");

我得到的输出将是-

嗨
你好
再见

所以没有什么可担心的。