C 字符串比较失败？
我有以下代码；
#include <stdio.h>
#define MAXLINE 2600
char words[4][MAXLINE];
int i;
int main(){
printf("Enter menu option: ");
scanf("%s", words[i]);
printf ("\n %s was entered!", words[i]);
if (words[i]=="help"){
printf("\nHelp was requested");
}
else
{
printf("\nCommand not recognized!");
}
}
if 语句中的数组评估不起作用。我显然做错了什么。有人可以向我解释什么吗？
Possible Duplicate:
C String — Using Equality Operator == for comparing two strings for equality
I have the following code;
#include <stdio.h>
#define MAXLINE 2600
char words[4][MAXLINE];
int i;
int main(){
printf("Enter menu option: ");
scanf("%s", words[i]);
printf ("\n %s was entered!", words[i]);
if (words[i]=="help"){
printf("\nHelp was requested");
}
else
{
printf("\nCommand not recognized!");
}
}
The array evaluation in the if statement isn't working. I am obviously doing something wrong. Can someone explain to me what?
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评论（2）
您正在比较
words[i]和"help"指针相等性，而不是字符串相等性。我认为你的意思是：if (strcmp(words[i], "help") == 0) {You are comparing
words[i]and"help"for pointer equality, not string equality. I think you meant:if (strcmp(words[i], "help") == 0) {在 C 中，字符串（字符序列）被视为字符数组。因此，您不应使用
==运算符来比较数组。数组大括号
[]只是语法糖，用于隐藏在幕后进行的指针算术。一般来说，arr[i]与*(arr + i)相同。使用此信息，让我们看一下您的比较：words[i]->*(words + i)，这是一个指向字符数组的指针。如果要比较字符串，请使用 strncmp。
In C, strings (sequences of characters) are treated as arrays of characters. As a result, you shouldn't compare arrays using the
==operator.The array braces
[]are just syntactic sugar to hide the pointer arithmetic that's going on under the hood. In general,arr[i]is identical to*(arr + i). Using this information, let's take a look at your comparison:words[i]->*(words + i), which is a pointer to an array of characters.If you want to compare strings, use strncmp.