在 Android 中解析 XML
我需要解析这个 XML：
<WhoisRecord xmlns="http://adam.kahtava.com/services/whois" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<DomainName>68.140.1.1</DomainName>
<RegistryData><AbuseContact><Email>[email protected]</Email><Name>abuse</Name><Phone>+1-800-900-0241</Phone></AbuseContact><AdministrativeContact><Email>[email protected]</Email><Name>Verizon Internet Services</Name><Phone>800-243-6994</Phone></AdministrativeContact><BillingContact i:nil="true"/><CreatedDate>2002-05-13T00:00:00-04:00</CreatedDate><RawText i:nil="true"/><Registrant><Address>22001 Loudoun County Parkway</Address><City>Ashburn</City><Country>US</Country><Name>UUNET Technologies, Inc.</Name><PostalCode>20147</PostalCode><StateProv>VA</StateProv></Registrant><TechnicalContact><Email>[email protected]</Email><Name>swipper</Name><Phone>+1-800-900-0241</Phone></TechnicalContact><UpdatedDate>2004-03-16T00:00:00-05:00</UpdatedDate><ZoneContact i:nil="true"/></RegistryData></WhoisRecord>
我的代码如下所示：
public class XMLParser
{
String streamTitle = "";
/** Called when the activity is first created.
* @throws IOException
* @throws SAXException */
public String startparse(String xml) throws SAXException, IOException
{
DocumentBuilderFactory builderFactory = DocumentBuilderFactory.newInstance();
try
{
DocumentBuilder builder = builderFactory.newDocumentBuilder();
builder.parse(xml);
}
catch (ParserConfigurationException e)
{
e.printStackTrace();
}
return builderFactory.getAttribute("WhoisRecord").toString();
}
}
当我尝试从 startparse 返回某些内容时，我什么也没得到。
XMLParser xmlpar = new XMLParser();
Log.v("Faruk TEST ", "udss:"+xmlpar.startparse(temp));
有人知道解决这个问题的简单方法吗？
Hy i need to parse this XML :
<WhoisRecord xmlns="http://adam.kahtava.com/services/whois" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<DomainName>68.140.1.1</DomainName>
<RegistryData><AbuseContact><Email>[email protected]</Email><Name>abuse</Name><Phone>+1-800-900-0241</Phone></AbuseContact><AdministrativeContact><Email>[email protected]</Email><Name>Verizon Internet Services</Name><Phone>800-243-6994</Phone></AdministrativeContact><BillingContact i:nil="true"/><CreatedDate>2002-05-13T00:00:00-04:00</CreatedDate><RawText i:nil="true"/><Registrant><Address>22001 Loudoun County Parkway</Address><City>Ashburn</City><Country>US</Country><Name>UUNET Technologies, Inc.</Name><PostalCode>20147</PostalCode><StateProv>VA</StateProv></Registrant><TechnicalContact><Email>[email protected]</Email><Name>swipper</Name><Phone>+1-800-900-0241</Phone></TechnicalContact><UpdatedDate>2004-03-16T00:00:00-05:00</UpdatedDate><ZoneContact i:nil="true"/></RegistryData></WhoisRecord>
My code looks like this:
public class XMLParser
{
String streamTitle = "";
/** Called when the activity is first created.
* @throws IOException
* @throws SAXException */
public String startparse(String xml) throws SAXException, IOException
{
DocumentBuilderFactory builderFactory = DocumentBuilderFactory.newInstance();
try
{
DocumentBuilder builder = builderFactory.newDocumentBuilder();
builder.parse(xml);
}
catch (ParserConfigurationException e)
{
e.printStackTrace();
}
return builderFactory.getAttribute("WhoisRecord").toString();
}
}
when i try to return something from startparse i simple get nothing.
XMLParser xmlpar = new XMLParser();
Log.v("Faruk TEST ", "udss:"+xmlpar.startparse(temp));
Do some one know a simple solution for this problem?
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评论（3）
试试这个，我希望这是您正在寻找的...
Android：从字符串中解析XML问题
Try this i hope it is what you are looking for ...
Android: parse XML from string problems
我认为您对 builderFactory.getAttribute 的调用是错误的。
DocumentBuilder.parse() 返回一个 Document 对象，它将包含您刚刚解析的 DOM。您可以使用它来访问 XML 的元素。
I think that your call to builderFactory.getAttribute is wrong.
DocumentBuilder.parse() returns a Document object, and this will contain the DOM that you've just parsed. You can use this to access the elements of the XML.
尝试使用 XML-Android
Try this Working with XML-Android