将 SELECT COUNT(*) 查询结果分配给 Java 变量

发布于 2024-11-03 18:06:11 字数 989 浏览 1 评论 0原文

我在将 SELECT COUNT(*) 查询的结果分配给 Java 变量时遇到问题。我将查询结果分配给 ResultSet。然后,我尝试检索计数的值并将其分配给变量。我在尝试执行此操作时遇到错误。

这是我的代码:

ResultSet rc1 = null;
int rowCount1;
Statement stat = conn.createStatement();

rc1 = stat.executeQuery("SELECT COUNT(*) AS rowcount1 
   FROM Signal WHERE SignalId = 1;");

if (rc1.next())
        rowCount1 = rc1.getInt("rowcount1");

然后我收到以下错误:

java.sql.SQLException:没有这样的列:'rowcount1'
在 org.sqlite.RS.findColumn(RS.java:116)
在 org.sqlite.RS.getInt(RS.java:219)

显然,问题在于尝试将 AS 之后的内容分配给变量时。我找不到很多关于包含 AS 的查询的信息。我在未计数的查询中遇到了同样的错误。例如,如果我有以下代码:

ResultSet rp1 = null;
int rowCount1 = 0;
Statement stat = conn.createStatement();

rp1 = stat.executeQuery("SELECT Signal AS Sig1 
  FROM Observations WHERE SignalId = 1;");

if (rp1.next())
       rowCount1 = rp1.getInt("rowcount1");

我会得到与之前的代码相同的错误(没有这样的列:rowCount1)。我做错了什么?我确保我正在读取的表包含正确的值,因此查询必须为真。

I have been having problems assigning the result of a SELECT COUNT(*) query to a Java variable. I am assigning the result of the query to a ResultSet. Then, I am trying to retrieve the value of the count and assigning it to a variable. I am getting an error when trying to do this.

Here is my code:

ResultSet rc1 = null;
int rowCount1;
Statement stat = conn.createStatement();

rc1 = stat.executeQuery("SELECT COUNT(*) AS rowcount1 
   FROM Signal WHERE SignalId = 1;");

if (rc1.next())
        rowCount1 = rc1.getInt("rowcount1");

Then I get the following error:

java.sql.SQLException: no such column: 'rowcount1'
at org.sqlite.RS.findColumn(RS.java:116)
at org.sqlite.RS.getInt(RS.java:219)

Apparently, the problem is when trying to assign what goes after AS to a variable. I can't find a lot of information on queries containing AS. I get the same error with queries where I am not counting. For example if I have the following code:

ResultSet rp1 = null;
int rowCount1 = 0;
Statement stat = conn.createStatement();

rp1 = stat.executeQuery("SELECT Signal AS Sig1 
  FROM Observations WHERE SignalId = 1;");

if (rp1.next())
       rowCount1 = rp1.getInt("rowcount1");

I get the same error with the previous code (no such column: rowCount1). What I am doing wrong? I am making sure the table I am reading contains the correct values so the query has to be true.

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(2

圈圈圆圆圈圈 2024-11-10 18:06:11

只需使用 rp1.getInt(1) 即可——这会以 int 形式返回结果集中的第一列——这就是您想要的。

如果您有更多值,请使用 rp1.getInt(2) 来获取第二个值等...

Simply use rp1.getInt(1) -- this returns the first column from the resultset as an int -- which is what you want.

If you have more values use rp1.getInt(2) to get the second value etc...

浮萍、无处依 2024-11-10 18:06:11

第二个示例有一个错误:

rp1 = stat.executeQuery("SELECT Signal AS Sig1 
  FROM Observations WHERE SignalId = 1;");
...
   rowCount1 = rp1.getInt("rowcount1")

将始终失败,因为查询中没有 rowcount1 列。

The second example has an error:

rp1 = stat.executeQuery("SELECT Signal AS Sig1 
  FROM Observations WHERE SignalId = 1;");
...
   rowCount1 = rp1.getInt("rowcount1")

will always fail because you have no rowcount1 column in your query.

~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文