问候所有
将数组中的最大数调整为第二个数组中的最小数的逻辑
我有一个数组“A”
A=[0 .1 .2 .3 .4 .5 .6 .7 .8 .9 1 .9 .8 .7 .6 .5 .4 .3 .2 .1 0 -.1 -.2 -.3 -.4 -.5 -.6 -.7 -.8 -.9 -1 -.9 -.8 -.7 -.6 -.5 -.4 -.3 -.2 -.1]
并且我希望第二个数组朝“相反”方向移动，因此当数组“A”中的数字变高时数组“B”中的数字应该变低
数组“B”应该是什么样子的示例（再次作为参考）
B=[1 .9 .8 .7 .6 .5 .4 .3 .2 .1 0 -.1 -.2 -.3 -.4 -.5 -.6 -.7 -.8 -.9 -1 -.9 -.8 -.7 -.6 -.5 -.4 -.3 -.2 -.1 0 .1 .2 .3 .4 .5 .6 .7 .8 .9]
A=[0 .1 .2 .3 .4 .5 .6 .7 .8 .9 1 .9 .8 .7 .6 .5 .4 .3 .2 .1 0 -.1 -.2 -.3 -.4 -.5 -.6 -.7 -.8 -.9 -1 -.9 -.8 -.7 -.6 -.5 -.4 -.3 -.2 -.1]
我尝试使用这个逻辑，但它当然使一切都积极，
arrayB=-abs(arrayA).+abs(max(arrayA));
但这不起作用我正在使用matlab但如果有人知道正确的逻辑我可以转换它在 matlab 语法
tia
中，数字代表信号的不同幅度，因此当一个信号数组 A 的幅度上升时，另一个信号数组 B 的幅度应该下降。存在“重叠”
Greetings all
logic for adjusting max number in array to min number in second array
I have an array "A"
A=[0 .1 .2 .3 .4 .5 .6 .7 .8 .9 1 .9 .8 .7 .6 .5 .4 .3 .2 .1 0 -.1 -.2 -.3 -.4 -.5 -.6 -.7 -.8 -.9 -1 -.9 -.8 -.7 -.6 -.5 -.4 -.3 -.2 -.1]
And I want the second array to be going in the "opposite" direction so when the numbers are going high in array "A" the numbers in array "B" should be going low
example of what array "B" should look like (and A again for reference)
B=[1 .9 .8 .7 .6 .5 .4 .3 .2 .1 0 -.1 -.2 -.3 -.4 -.5 -.6 -.7 -.8 -.9 -1 -.9 -.8 -.7 -.6 -.5 -.4 -.3 -.2 -.1 0 .1 .2 .3 .4 .5 .6 .7 .8 .9]
A=[0 .1 .2 .3 .4 .5 .6 .7 .8 .9 1 .9 .8 .7 .6 .5 .4 .3 .2 .1 0 -.1 -.2 -.3 -.4 -.5 -.6 -.7 -.8 -.9 -1 -.9 -.8 -.7 -.6 -.5 -.4 -.3 -.2 -.1]
I tried using this logic but it makes everything positive of course
arrayB=-abs(arrayA).+abs(max(arrayA));
but that didn't work I'm using matlab but if someone knows the correct logic I can convert it over the matlab syntax
tia
The numbers represent different amplitudes of a signal so when the amplitude of one signal arrayA is going up the other signal arrayB should be going down. There is "overlap"
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评论（4）
您的标题和描述非常令人困惑，我无法从中看出您想要做什么。但是，查看您想要从输入数组
A生成的所需输出数组B，我可以为您提供一些操作将为您进行转换：这会找到绝对 数组
A中值的差异，将这些差异相乘通过A元素的 符号 （通过添加将 0 计为正数EPS 到信号），采用 这些值的累积和，然后从A中的最大值。这种情况下的另一个解决方案是使用 A 的循环移位="nofollow">数组索引。例如，移动数组
A使其最大值位于数组的开头，将得到所需的数组B：Your title and description are very confusing, and I'm unable to tell from them what you are trying to do. However, looking at the desired output array
Bthat you want to generate from your input arrayA, I can give you a couple of operations that will do that transformation for you:This finds the absolute differences in values along array
A, multiplies these differences by the sign of the elements ofA(counting 0 as positive by adding EPS to the signal), takes the cumulative sum of these values, then subtracts them from the maximum value inA.Another solution in this case is simply to create a circular shift of
Ausing array indexing. For example, shifting the arrayAsuch that its maximum value is at the beginning of the array will give you the desired arrayB:Rick，
是不是像 B[i] = 1 - abs(A[i]) 一样简单……还是我遗漏了一些东西？
负面因素很快就会停止排列，这使得人们很难看出其中的关系。
干杯。基思.
编辑：不，事情没那么简单！
没有“普通计算”可以产生这些结果。
一切都很好，直到我们达到
.1 0 -.1...，它产生-.9 -1 -.9我猜你必须“走过它”以 10 为单位，每 10 后交换结果的符号。
这有什么意义吗？你可以明白为什么我没有做高级数学。
干杯。基思.
Rick,
Is it as simple as B[i] = 1 - abs(A[i]) ... or am I missing something?
The negatives soon stop lining up, which makes it difficult to see the relationship.
Cheers. Keith.
EDIT: Nope, it's not that simple!
There is no "ordinary computation" which will produce these results.
It's all good untill we get upto
.1 0 -.1... which produces-.9 -1 -.9I guess you'd have to "walk through it" by 10's, swapping the sign of the result after each 10.
Does that make ANY sense? You can see why I didn't do Higher Level maths.
Cheers. Keith.
下面的代码或多或少符合您的要求吗？
Does the following code does more or less what you want?
这也将创建正确的答案
This will also create the correct answer