如何消除错误？

Question

我正在编写文本编辑器，它实际上应该说出当前按下的键。我设法做到了，我什至准备了文件。一切都工作正常，但是当符号数量超过 29 时，编译器会说：

javax.sound.sampled.LineUnavailableException: unable to obtain a line
at org.classpath.icedtea.pulseaudio.PulseAudioDataLine.connect(PulseAudioDataLine.java:279)
at org.classpath.icedtea.pulseaudio.PulseAudioDataLine.open(PulseAudioDataLine.java:102)
at org.classpath.icedtea.pulseaudio.PulseAudioDataLine.open(PulseAudioDataLine.java:289)
at org.classpath.icedtea.pulseaudio.PulseAudioClip.open(PulseAudioClip.java:402)
at org.classpath.icedtea.pulseaudio.PulseAudioClip.open(PulseAudioClip.java:453)
at TextEditor$AreaListener.keyPressed(Main.java:81)
at java.awt.Component.processKeyEvent(Component.java:6161)
at javax.swing.JComponent.processKeyEvent(JComponent.java:2801)
at java.awt.Component.processEvent(Component.java:5980)
at java.awt.Container.processEvent(Container.java:2105)
at java.awt.Component.dispatchEventImpl(Component.java:4564)
at java.awt.Container.dispatchEventImpl(Container.java:2163)
at java.awt.Component.dispatchEvent(Component.java:4390)
at java.awt.KeyboardFocusManager.redispatchEvent(KeyboardFocusManager.java:1881)
at java.awt.DefaultKeyboardFocusManager.dispatchKeyEvent(DefaultKeyboardFocusManager.java:749)
at java.awt.DefaultKeyboardFocusManager.preDispatchKeyEvent(DefaultKeyboardFocusManager.java:1025)
at java.awt.DefaultKeyboardFocusManager.typeAheadAssertions(DefaultKeyboardFocusManager.java:892)
at java.awt.DefaultKeyboardFocusManager.dispatchEvent(DefaultKeyboardFocusManager.java:713)
at java.awt.Component.dispatchEventImpl(Component.java:4434)
at java.awt.Container.dispatchEventImpl(Container.java:2163)
at java.awt.Window.dispatchEventImpl(Window.java:2478)
at java.awt.Component.dispatchEvent(Component.java:4390)
at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:649)
at java.awt.EventQueue.access$000(EventQueue.java:96)
at java.awt.EventQueue$1.run(EventQueue.java:608)
at java.awt.EventQueue$1.run(EventQueue.java:606)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.AccessControlContext$1.doIntersectionPrivilege(AccessControlContext.java:105)
at java.security.AccessControlContext$1.doIntersectionPrivilege(AccessControlContext.java:116)
at java.awt.EventQueue$2.run(EventQueue.java:622)
at java.awt.EventQueue$2.run(EventQueue.java:620)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.AccessControlContext$1.doIntersectionPrivilege(AccessControlContext.java:105)
at java.awt.EventQueue.dispatchEvent(EventQueue.java:619)
at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:275)
at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:200)
at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:190)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:185)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:177)
at java.awt.EventDispatchThread.run(EventDispatchThread.java:138)

这是我的源代码的一部分，其中描述了一个实现 KeyListener 接口的类。这个类是我的主文本区域的监听器。

class AreaListener implements KeyListener {
    @Override public void keyPressed( KeyEvent e) {
        try {
            AudioInputStream result1 = AudioSystem.getAudioInputStream(new File("/home/nikkka/Desktop/alphabet/blank.wav"));;
            if(new Character(e.getKeyChar()).isLetter(e.getKeyChar()))
                result1 = AudioSystem.getAudioInputStream(new File("/home/nikkka/Desktop/alphabet/"+e.getKeyChar()+"_EDITOR.wav"));
            DataLine.Info info = new DataLine.Info(Clip.class, result1.getFormat());
            Clip clip = (Clip) AudioSystem.getLine(info);
            clip.open(result1);
            clip.start();
        } catch(Exception e1) {e1.printStackTrace();}}
    @Override public void keyReleased(KeyEvent e) {}
    @Override public void keyTyped(   KeyEvent e) {
    }
}

我看不出问题是什么？...此外，为什么适用于前 29 个符号的东西不应该适用于更多符号？也许是因为我必须在 clip.start() 之后通过 clip.close() 关闭剪辑？请帮忙:-S

Answer 1

您收到此错误是因为 根据描述的文档，由于资源限制，线路不可用这里。

我认为你应该关闭 Line 与 Line.close() 方法。

编辑：
正确的方法如下：

1. 在启动应用程序时创建一个 Clip 对象，或者创建用于处理输入区域的对象，
2. 在按下按键时使用该 Clip 对象在输入区域中的
3. stop() 和 close() 当应用程序退出或销毁输入区域时 Clip

这将节省资源。

Answer 2

这不是编译器错误消息。

这是一个运行时错误，我认为这意味着它无法读取声音文件中的数据。文件已损坏或格式不受支持。