针对方案中的列表列表运行查询

发布于 2024-11-02 21:28:30 字数 378 浏览 0 评论 0原文

我被困在我的项目中。我有一个列表列表，例如：

'((a for apple) (b is book) (c in cat) (ronn live in NY))

现在我想以列表的形式进行查询，并让它在我的列表列表中显示正确的条目。例如，如果我输入 '(a for what) 或 '(what in cat) 它将显示 (a for apple) 或 <代码>（猫中的c）。如果我输入'(ronn live in where)，它将显示(ronn live in NY)。

谁能帮我解决这个问题吗？

原文

I'm stuck in the middle of my project. I have a list of lists like:

'((a for apple) (b is book) (c in cat) (ronn live in NY))

Now I want to make a query in the form of a list and have it display the correct entry in my list of lists. For example, if I input '(a for what) or '(what in cat) it will display (a for apple) or (c in cat). If I input '(ronn live in where) it will show (ronn live in NY).

Can anyone help me solve this problem?

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空宴 2024-11-09 21:28:30

如何在列表中运行 filter 例程，并使用用查询信息初始化的 lambda 对象，然后将其应用于列表，直到找到匹配项。

例如，您将有一个看起来像这样的 lamda

(define (filter-object query)
    (define (query-function list-input)
        ;;do something here for query function that will take the initialized
        ;;query and match it against the list-input to see if there's a match
        ;;it should return #t or #f
    )

    ;;the return of the filter-object is the query function
    query_function) 

;;my-filter-function is initialized with a specific query
(define my-filter-function (filter-object '(a for what)))

现在，在初始化了 filter-object 的情况下，在您的列表中运行一个过滤器

(define (filter filter-function list-of-lists)
    (cond ((eq? list-of-lists '()) '())
          ((filter-function (car list-of-lists))
           (cons (car list-of-lists)
              (filter filter-function (cdr list-of-lists)))
          (else (filter filter-function (cdr list-of-lists))))

(filter my-filter-function my-list)

这应该返回一个匹配的单元素列表（假设您是不要在您的列表集中放置多个副本，

希望这会有所帮助，

杰森。

How about running a filter routine across the list, and using a lambda object initialized with your query information that will then be applied to the list until it finds a match.

So for instance, you would have a lamda that would look something like

(define (filter-object query)
    (define (query-function list-input)
        ;;do something here for query function that will take the initialized
        ;;query and match it against the list-input to see if there's a match
        ;;it should return #t or #f
    )

    ;;the return of the filter-object is the query function
    query_function) 

;;my-filter-function is initialized with a specific query
(define my-filter-function (filter-object '(a for what)))

Now with the filter-object initialized, run a filter across your list

(define (filter filter-function list-of-lists)
    (cond ((eq? list-of-lists '()) '())
          ((filter-function (car list-of-lists))
           (cons (car list-of-lists)
              (filter filter-function (cdr list-of-lists)))
          (else (filter filter-function (cdr list-of-lists))))

(filter my-filter-function my-list)

This should return a one-element list of the matches (providing you aren't placing more than one copy in your list set.

Hope this helps,

Jason

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