在 Ruby 中调用超级方法

发布于 2024-11-02 20:24:23 字数 284 浏览 5 评论 0原文

我试图在 Ruby 中定义一些具有继承层次结构的类，但我想在派生类中使用基类中的方法之一。不同的是，我不想调用我所在的确切方法，我想调用另一个不同的方法。以下不起作用，但这是我想做的（基本上）。

class A
    def foo
        puts 'A::foo'
    end
end

class B < A
    def foo
        puts 'B::foo'
    end
    def bar
        super.foo
    end
end

原文

I am trying to define some classes in Ruby that have an inheritance hierarchy, but I want to use one of the methods in the base class in the derived class. The twist is that I don't want to call the exact method I'm in, I want to call a different one. The following doesn't work, but it's what I want to do (basically).

class A
    def foo
        puts 'A::foo'
    end
end

class B < A
    def foo
        puts 'B::foo'
    end
    def bar
        super.foo
    end
end

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Saygoodbye 2024-11-09 20:24:23

也许，这就是你想要的？

class A
  def foo
    puts 'A::foo'
  end
end

class B < A
  alias bar :foo
  def foo
    puts 'B::foo'
  end
end

B.new.foo # => B::foo
B.new.bar # => A::foo

Probably, this is what you want?

class A
  def foo
    puts 'A::foo'
  end
end

class B < A
  alias bar :foo
  def foo
    puts 'B::foo'
  end
end

B.new.foo # => B::foo
B.new.bar # => A::foo

回复收藏 0 原文

探春 2024-11-09 20:24:23

更通用的解决方案。

class A
  def foo
    puts "A::foo"
  end
end

class B < A
  def foo
    puts "B::foo"
  end
  def bar
    # slightly oddly ancestors includes the class itself
    puts self.class.ancestors[1].instance_method(:foo).bind(self).call
  end
end

B.new.foo # => B::foo
B.new.bar # => A::foo

A more general solution.

class A
  def foo
    puts "A::foo"
  end
end

class B < A
  def foo
    puts "B::foo"
  end
  def bar
    # slightly oddly ancestors includes the class itself
    puts self.class.ancestors[1].instance_method(:foo).bind(self).call
  end
end

B.new.foo # => B::foo
B.new.bar # => A::foo

回复收藏 0 原文

~没有更多了~