从输入流获取文件名 (Java)
如果我有这段代码，我如何保留原始文件的文件名或将其重新分配给新文件？：
InputStream input= assetInfo.openStream();
File t = new File("");
OutputStream out = new FileOutputStream(t);
int read=0;
byte[] bytes = new byte[1024];
while((read = input.read(bytes))!= -1){
out.write(bytes, 0, read);
}
if I have this code, how could I keep the filename of the original file or reassign it to the new one?:
InputStream input= assetInfo.openStream();
File t = new File("");
OutputStream out = new FileOutputStream(t);
int read=0;
byte[] bytes = new byte[1024];
while((read = input.read(bytes))!= -1){
out.write(bytes, 0, read);
}
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可以创建输入流以从文件或任何其他数据源读取。因此，将文件名附加到输入流是没有意义的。查看 assetInfo 来查看该类是否公开该数据（您甚至可以使用反射查看该类的内部）。请注意，创建者或
assetInfo犯了一个设计错误，没有公开此信息，或者您现在正尝试这样做。An input stream can be created to read from a file or from any other source of data. Therefore it makes no sense to have a filename attached to an input stream. Look in
assetInfoto see if that class exposes that data (you can even look inside the class using reflection). Note that the creator orassetInfomade a design mistake not exposing this information, OR you are trying to make one now.