使用 JavaScript 搜索 JSON 中的字符

发布于 2024-11-02 18:42:10 字数 473 浏览 0 评论 0原文

[
{"lastName":"Noyce","gender":"Male","patientID":19389,"firstName":"Scott","age":"53Y,"}, 
{"lastName":"noyce724","gender":"Male","patientID":24607,"firstName":"rita","age":"0Y,"}
]

将我的输入与 JSON 进行比较。

for (var i = 0; i < recentPatientsList.length; ++i) {
  if (searchBarInput === recentPatientsList[i].lastName) {
    alert("Found at index " + i);
  }
}

这样我就可以查看我的输入是否与 JSON 匹配。我如何获得姓氏以“N”开头或给定输入的数据的结果。

原文

[
{"lastName":"Noyce","gender":"Male","patientID":19389,"firstName":"Scott","age":"53Y,"}, 
{"lastName":"noyce724","gender":"Male","patientID":24607,"firstName":"rita","age":"0Y,"}
]

Comparing my input with the JSON.

for (var i = 0; i < recentPatientsList.length; ++i) {
  if (searchBarInput === recentPatientsList[i].lastName) {
    alert("Found at index " + i);
  }
}

With this i am able to see whether i match my input with the JSON. How can i get results of data whose last name starts with 'N' or given input.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

哎呦我呸! 2024-11-09 18:42:10

假设您 searchBarInput 等于 "n"，试试这个：

var results = []; // initialize array of results
for (var i = 0; i < recentPatientsList.length; ++i) {
  if (recentPatientsList[i].lastName.indexOf(searchBarInput) == 0) {
    results.push(recentPatientsList[i].lastName);
  }
}
alert('Results: ' + results.toString());

Assuming you searchBarInput is equal to "n", Try this:

var results = []; // initialize array of results
for (var i = 0; i < recentPatientsList.length; ++i) {
  if (recentPatientsList[i].lastName.indexOf(searchBarInput) == 0) {
    results.push(recentPatientsList[i].lastName);
  }
}
alert('Results: ' + results.toString());

回复收藏 0 原文

~没有更多了~