R：如何根据列名和行名合并两个矩阵？

Question

输入矩阵A

       column1   column2   column3   column4
row1   0         1         0         0
row2   0         0         -1        0
row3   1         0         0         -1

输入矩阵B

       column5   column6   column7   column8
row1   0         1         0         0
row2   0         0         -1        0
row4   1         0         0         -1

输出矩阵C

       column1   column2   column3   column4    column5   column6   column7   column8
row1   0         1         0         0          0         1         0         0
row2   0         0         -1        0          0         0         -1        0
row3   1         0         0         -1         0         0         0         0
row4   0         0         0         0          1         0         0         -1

备注：矩阵A 和矩阵B 的行名重叠。但是，所有列的名称都不同。

Answer 1

您可以使用 merge 来通过指定可选参数 by 和 all 来完成此操作：

#Reading data
txt1 <- "column1   column2   column3   column4
row1   0         1         0         0
row2   0         0         -1        0
row3   1         0         0         -1
"

txt2 <- "column5   column6   column7   column8
row1   0         1         0         0
row2   0         0         -1        0
row4   1         0         0         -1
"
dat1 <- read.table(textConnection(txt1), header = TRUE)
dat2 <- read.table(textConnection(txt2), header = TRUE)

#Merge them together
merge(dat1, dat2, by = "row.names", all = TRUE)

将产生

Row.names column1 column2 column3 column4 column5 column6 column7 column8
1      row1       0       1       0       0       0       1       0       0
2      row2       0       0      -1       0       0       0      -1       0
3      row3       1       0       0      -1      NA      NA      NA      NA
4      row4      NA      NA      NA      NA       1       0       0      -1

如果您想将 NA 替换为零，则此操作应该工作：

#Assign to an object
zz <- merge(dat1, dat2, by = "row.names", all = TRUE)
#Replace NA's with zeros
zz[is.na(zz)] <- 0