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删除 matplotlib 图上的图例

发布于 2024-11-02 17:07:21 字数 170 浏览 5 评论 0原文

要向 matplotlib 绘图添加图例，只需运行 legend() 即可。

如何从图中删除图例？

（我最接近的方法是运行 legend([]) 来清空数据中的图例。但这会在右上角留下一个丑陋的白色矩形。）

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别挽留 2024-11-09 17:07:21

自 matplotlib v1.4.0rc4 ，一个 remove 方法已添加到图例对象中。

用法：

ax.get_legend().remove()

或者

legend = ax.legend(...)
...
legend.remove()

请参阅此处了解引入此功能的提交。

As of matplotlib v1.4.0rc4, a remove method has been added to the legend object.

Usage:

ax.get_legend().remove()

legend = ax.legend(...)
...
legend.remove()

See here for the commit where this was introduced.

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与风相奔跑 2024-11-09 17:07:21

如果要绘制 Pandas 数据框并删除图例，请将 legend=None 作为参数添加到绘图命令中。

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt

df2 = pd.DataFrame(np.random.randn(10, 5))
df2.plot(legend=False)
plt.show()

If you want to plot a Pandas dataframe and want to remove the legend, add legend=None as parameter to the plot command.

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt

df2 = pd.DataFrame(np.random.randn(10, 5))
df2.plot(legend=False)
plt.show()

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阳光下慵懒的猫 2024-11-09 17:07:21

您可以使用图例的 set_visible 方法：

ax.legend().set_visible(False)
draw()

这是基于我为回答我不久前遇到的类似问题而提供的答案此处

（感谢 Jouni 的回答 - 很抱歉，我无法将问题标记为已回答......也许有权限的人可以这样做为我？）

You could use the legend's set_visible method:

ax.legend().set_visible(False)
draw()

This is based on a answer provided to me in response to a similar question I had some time ago here

(Thanks for that answer Jouni - I'm sorry I was unable to mark the question as answered... perhaps someone who has the authority can do so for me?)

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琉璃繁缕 2024-11-09 17:07:21

如果您将 pyplot 调用为 plt

frameon=False 是为了删除图例周围的边框

，并且 '' 正在传递不应有任何变量的信息传说中

import matplotlib.pyplot as plt
plt.legend('',frameon=False)

if you call pyplot as plt

frameon=False is to remove the border around the legend

and '' is passing the information that no variable should be in the legend

import matplotlib.pyplot as plt
plt.legend('',frameon=False)

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孤凫 2024-11-09 17:07:21

您必须添加以下代码行：

ax = gca()
ax.legend_ = None
draw()

gca() 返回当前轴句柄，并具有该属性 legend_

you have to add the following lines of code:

ax = gca()
ax.legend_ = None
draw()

gca() returns the current axes handle, and has that property legend_

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烟燃烟灭 2024-11-09 17:07:21

根据@naitsirhc的信息，我想找到官方的API文档。这是我的发现和一些示例代码。

我通过 seaborn 创建了一个 matplotlib.Axes 对象。散点图（）。
ax.get_legend() 将返回一个 matplotlib.legend.Legend 实例。
最后，您调用 .remove() 函数从图中删除图例。

ax = sns.scatterplot(......)
_lg = ax.get_legend()
_lg.remove()

如果您检查 matplotlib.legend.LegendAPI 文档中，您不会看到 .remove() 函数。

原因是 matplotlib.legend.Legend 继承了 matplotlib.artist.Artist。因此，当您调用 ax.get_legend().remove() 时，基本上会调用 matplotlib.artist.Artist.remove()。

最后，您甚至可以将代码简化为两行。

ax = sns.scatterplot(......)
ax.get_legend().remove()

According to the information from @naitsirhc, I wanted to find the official API documentation. Here are my finding and some sample code.

I created a matplotlib.Axes object by seaborn.scatterplot().
The ax.get_legend() will return a matplotlib.legend.Legend instance.
Finally, you call .remove() function to remove the legend from your plot.

ax = sns.scatterplot(......)
_lg = ax.get_legend()
_lg.remove()

If you check the matplotlib.legend.Legend API document, you won't see the .remove() function.

The reason is that the matplotlib.legend.Legend inherited the matplotlib.artist.Artist. Therefore, when you call ax.get_legend().remove() that basically call matplotlib.artist.Artist.remove().

In the end, you could even simplify the code into two lines.

ax = sns.scatterplot(......)
ax.get_legend().remove()

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指尖上得阳光 2024-11-09 17:07:21

我通过将其添加到图形而不是轴（matplotlib 2.2.2）来制作图例。要删除它，我将图窗的 legends 属性设置为空列表：

import matplotlib.pyplot as plt

fig = plt.figure()
ax1 = fig.add_subplot(111)
ax2 = ax1.twinx()

ax1.plot(range(10), range(10, 20), label='line 1')
ax2.plot(range(10), range(30, 20, -1), label='line 2')

fig.legend()

fig.legends = []

plt.show()

I made a legend by adding it to the figure, not to an axis (matplotlib 2.2.2). To remove it, I set the legends attribute of the figure to an empty list:

import matplotlib.pyplot as plt

fig = plt.figure()
ax1 = fig.add_subplot(111)
ax2 = ax1.twinx()

ax1.plot(range(10), range(10, 20), label='line 1')
ax2.plot(range(10), range(30, 20, -1), label='line 2')

fig.legend()

fig.legends = []

plt.show()

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清旖 2024-11-09 17:07:21

如果您不使用无花果和斧头图对象，您可以这样做：

import matplotlib.pyplot as plt

# do plot specifics
plt.legend('')
plt.show()

If you are not using fig and ax plot objects you can do it like so:

import matplotlib.pyplot as plt

# do plot specifics
plt.legend('')
plt.show()

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空城仅有旧梦在 2024-11-09 17:07:21

以下是使用 matplotlib 和 seaborn 处理子图的图例删除和操作的更复杂示例：

从 seaborn 中获取由 Axes 创建的 Axes 对象code>sns.() 并按照 @naitsirhc。下面的示例还展示了如何将图例放在一边，以及如何处理子图的上下文。

# imports
import seaborn as sns
import matplotlib.pyplot as plt

# get data
sns.set()
sns.set_theme(style="darkgrid")
tips = sns.load_dataset("tips")

# subplots
fig, axes = plt.subplots(1, 2, sharex=True, sharey=True, figsize=(12,6)) 
fig.suptitle('Example of legend manipulations on subplots with seaborn')

g0 = sns.pointplot(ax=axes[0], data=tips, x="day", y="total_bill", hue="size")
g0.set(title="Pointplot with no legend")
g0.get_legend().remove() # <<< REMOVE LEGEND HERE 

g1 = sns.swarmplot(ax=axes[1], data=tips, x="day", y="total_bill", hue="size")
g1.set(title="Swarmplot with legend aside")
# change legend position: https://www.statology.org/seaborn-legend-position/
g1.legend(bbox_to_anchor=(1.02, 1), loc='upper left', borderaxespad=0)

Here is a more complex example of legend removal and manipulation with matplotlib and seaborn dealing with subplots:

From seaborn, get the Axes object created by sns.<some_plot>() and do ax.get_legend().remove() as indicated by @naitsirhc. The following example also shows how to put the legend aside, and how to deal in a context of subplots.

# imports
import seaborn as sns
import matplotlib.pyplot as plt

# get data
sns.set()
sns.set_theme(style="darkgrid")
tips = sns.load_dataset("tips")

# subplots
fig, axes = plt.subplots(1, 2, sharex=True, sharey=True, figsize=(12,6)) 
fig.suptitle('Example of legend manipulations on subplots with seaborn')

g0 = sns.pointplot(ax=axes[0], data=tips, x="day", y="total_bill", hue="size")
g0.set(title="Pointplot with no legend")
g0.get_legend().remove() # <<< REMOVE LEGEND HERE 

g1 = sns.swarmplot(ax=axes[1], data=tips, x="day", y="total_bill", hue="size")
g1.set(title="Swarmplot with legend aside")
# change legend position: https://www.statology.org/seaborn-legend-position/
g1.legend(bbox_to_anchor=(1.02, 1), loc='upper left', borderaxespad=0)

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失与倦＂ 2024-11-09 17:07:21

如果您使用的是seaborn，则可以使用参数legend。即使您在同一个图中多次绘制。一些 df 的示例

import seaborn as sns

# Will display legend
ax1 = sns.lineplot(x='cars', y='miles', hue='brand', data=df)

# No legend displayed
ax2 = sns.lineplot(x='cars', y='miles', hue='brand', data=df, legend=None)

If you are using seaborn you can use the parameter legend. Even if you are ploting more than once in the same figure. Example with some df

import seaborn as sns

# Will display legend
ax1 = sns.lineplot(x='cars', y='miles', hue='brand', data=df)

# No legend displayed
ax2 = sns.lineplot(x='cars', y='miles', hue='brand', data=df, legend=None)

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