导航控制器后退按钮可转到上一屏幕之前的屏幕
我想知道是否可以使用导航控制器按钮返回到上一页。现在，我已经使用此代码自定义了按钮
self.navigationItem.leftBarButtonItem =
[[UIBarButtonItem alloc] initWithTitle:mainLib.navCountryTitle
style:UIBarButtonItemStyleBordered
target:self
action:@selector(handleBack:)];
，在“handleback”方法中，我调用了这一行
[self.navigationController popViewControllerAnimated:YES];
所以在这种情况下它将转到上一个屏幕。但是我想转到上一个屏幕之前的屏幕。
我知道我可以立即调用该屏幕，但我不想这样做，因为在每个屏幕中我都有一个后退按钮，该按钮应该转到其上一个屏幕。
I'm wondering whether it's possible to go back to 2 previous page using navigation controller button. Right now, I've custom made the button using this code
self.navigationItem.leftBarButtonItem =
[[UIBarButtonItem alloc] initWithTitle:mainLib.navCountryTitle
style:UIBarButtonItemStyleBordered
target:self
action:@selector(handleBack:)];
And on 'handleback' method, I called this line
[self.navigationController popViewControllerAnimated:YES];
So in this case it will go to the previous screen. However I want to go to the screen before the previous screen.
I know that i can call that screen straight away, but I wouldn't want to do that because in every screen I have a back button which supposed to go to its previous screen.
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您可以使用其推送索引弹出到特定的视图控制器。如果您知道语法，那么您可以像
我相信的那样这样做，在您的情况下，它将是第一个索引。尽管您可以再次更改索引并检查。
这里 self.navigationController.viewControllers 是推送的所有 ViewController 的数组。
希望有帮助。
You can pop to particular viewcontroller using its pushing index. If you know the syntax than you can do that like
I believe, In your case it would be 1st Index. Though you can again change index and check.
Here self.navigationController.viewControllers is the array of the all the ViewControllers pushed.
Hope it helps.