通过给出“不包含在聚合函数中”来进行自连接和分组(SQL 服务器)

发布于 2024-11-02 13:48:09 字数 552 浏览 3 评论 0原文

再会, 这就是我想要做的......

ITEM   |   CATEGORY    |    AMOUNT
Sponge         A              29
Sponge         B              32
Sponge         C              33
Sponge         D              34
Rod            A               1
Rod            B               2
Rod            C               3
Rod            D               4

我希望输出看起来像这样:

ITEM    |   A   |  B   |   C   |   D
Sponge     29      32      33      34
Rod        1       2       3        5

我一直在尝试 GROUP BY 的各种组合,但我似乎无法让它工作。

Good day,
Here's what I'm trying to do..

ITEM   |   CATEGORY    |    AMOUNT
Sponge         A              29
Sponge         B              32
Sponge         C              33
Sponge         D              34
Rod            A               1
Rod            B               2
Rod            C               3
Rod            D               4

And I wanted the output to look like this:

ITEM    |   A   |  B   |   C   |   D
Sponge     29      32      33      34
Rod        1       2       3        5

I've been trying all sorts of combinations of GROUP BY but I can't seem to get it to work.

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我一向站在原地 2024-11-09 13:48:09
SELECT ITEM
      ,MAX(CASE WHEN CATEGORY ='A' THEN Amount END) AS A
      ,MAX(CASE WHEN CATEGORY ='B' THEN Amount END) AS B
      ,MAX(CASE WHEN CATEGORY ='C' THEN Amount END) AS C
      ,MAX(CASE WHEN CATEGORY ='D' THEN Amount END) AS D
FROM YourTable
GROUP BY ITEM

或者

SELECT *
FROM YourTable
PIVOT (MAX(AMOUNT) FOR CATEGORY IN ([A],[B],[C],[D])) AS Pvt
SELECT ITEM
      ,MAX(CASE WHEN CATEGORY ='A' THEN Amount END) AS A
      ,MAX(CASE WHEN CATEGORY ='B' THEN Amount END) AS B
      ,MAX(CASE WHEN CATEGORY ='C' THEN Amount END) AS C
      ,MAX(CASE WHEN CATEGORY ='D' THEN Amount END) AS D
FROM YourTable
GROUP BY ITEM

Or

SELECT *
FROM YourTable
PIVOT (MAX(AMOUNT) FOR CATEGORY IN ([A],[B],[C],[D])) AS Pvt
橘亓 2024-11-09 13:48:09
WITH    q AS
        (
        SELECT  *
        FROM    (
                VALUES
                ('Sponge', 'A', 29),
                ('Sponge', 'B', 32),
                ('Sponge', 'C', 33),
                ('Sponge', 'D', 34),
                ('Rod', 'A', 1),
                ('Rod', 'B', 2),
                ('Rod', 'C', 3),
                ('Rod', 'D', 4)
                ) q (item, category, amount)
        )
SELECT  *
FROM    q
PIVOT   (
        MAX(amount)
        FOR     category IN ([A], [B], [C], [D])
        ) AS qp
WITH    q AS
        (
        SELECT  *
        FROM    (
                VALUES
                ('Sponge', 'A', 29),
                ('Sponge', 'B', 32),
                ('Sponge', 'C', 33),
                ('Sponge', 'D', 34),
                ('Rod', 'A', 1),
                ('Rod', 'B', 2),
                ('Rod', 'C', 3),
                ('Rod', 'D', 4)
                ) q (item, category, amount)
        )
SELECT  *
FROM    q
PIVOT   (
        MAX(amount)
        FOR     category IN ([A], [B], [C], [D])
        ) AS qp
~没有更多了~
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