回显退格键
是否可以在 bash 中回显退格键？
类似的东西
echo $'stack\b'
不应该输出 stac?或者我错过了什么？
更具体地说，我想将其用于：
ls | wc -l; echo $'\b items'
Is it possible to echo a backspace in bash?
Something like
echo
Shouldn't output stac? Or I'm missing something?
More specifically, I'd like to use that in:
ls | wc -l; echo
stack\b'
Shouldn't output stac? Or I'm missing something?
More specifically, I'd like to use that in:
\b items'
Shouldn't output stac? Or I'm missing something?
More specifically, I'd like to use that in:
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\b使光标向左移动，但不会删除该字符。如果要删除则输出一个空格。对于某些发行版，您可能还需要使用
echo的-e开关：所以它看起来像
Also,
files=(*) ;回显“${#files[@]} 项”。\bmakes the cursor move left, but it does not erase the character. Output a space if you want to erase it.For some distributions you may also need to use
-eswitch ofecho:So it will look like
Also,
files=(*) ; echo "${#files[@]} items".因此，为了回答有关退格键的实际问题，这将模拟退格键：
它将字符向后移动一个，然后回显一个空格，覆盖那里的任何字符，然后再次向后移动 - 实际上删除前一个字符。但它不会返回一行，因此之前的输出不应创建新行：
So to answer the actual question about backspaces this will simulate a backspace:
It will move the character back one, then echo a space overwriting whatever character was there, then moving back again - in effect deleting the previous character. It won't go back up a line though so the output before that should not create a new line:
这并不完全是您所要求的，而且，在伊格纳西奥的回答中，您可以用于这种情况：
据我所知，您无法打印删除之前字符的字符，甚至无法打印其十六进制数字对应的字符退格键。不过，您可以后退并打印一个空格来删除。使用cput，您可以执行许多操作并在屏幕上的任意位置进行打印。
It is not exactly what you're asking for, but also, in the line of Ignacio's answer, you could use for this case:
AFAIK you cannot print a character that deletes the one before, not even printing the char whose hexadecimanl number correspoonds to backspace. You can move back and print a blank space to delete, though. With cput you can do many things and print wherever you want in the screen.