使用正则表达式将所有进行中的下划线替换为 1 个下划线？
我需要一些帮助，我有一个如下所示的字符串：
$p__________________________________________________________________________________________________________________________________________, &$s___________________________________________________________________________________________________________________________________________, &$k____________________________________________________________________________________________________________________________________________, &$nft_____________________________________________________________________________________________________________________________________________)
并且想知道是否可以使用正则表达式将其变成：
$p_, &$s_, &$k_, &$nft_)
这基本上是删除所有（所以他们没有具体数量，但他们至少 1）进行下划线，并替换它们带有 1 个下划线。
我尝试过以下模式，但没有成功：
preg_replace('#(\$[a-z]{1,3})[_]+#', '$1', $string);
PS：首选 preg_replace （正则表达式）的原因（尽管我知道它并非 100% 总是正确），因为它比使用常规字符串替换函数更精确。
感谢并感谢所有帮助。
I need some help, I have a string which looks like below:
$p__________________________________________________________________________________________________________________________________________, &$s___________________________________________________________________________________________________________________________________________, &$k____________________________________________________________________________________________________________________________________________, &$nft_____________________________________________________________________________________________________________________________________________)
and was wondering if I could use a regex to turn it into:
$p_, &$s_, &$k_, &$nft_)
Which is basically removing all the (so theirs no specific amount but theirs atleast 1) proceeding underscores, and replace them with 1 underscore.
I've tried the following pattern but no luck:
preg_replace('#(\$[a-z]{1,3})[_]+#', '$1', $string);
PS: The reason a preg_replace (regex) is preffered (although I understand its not 100% always correct) because it's more precise then using a regular string replacing function.
Thanks and appreciate all help.
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考虑到如此简单的事情，您可以从 str_replace() 获得更好的性能。
thought for something so simple, you'd get better performance from str_replace().
您可以尝试使用“str_replace”将 _ 替换为空格，然后在右侧修剪空格！然后在字符串末尾添加_。我不知道直接的方法抱歉！我认为这比正则表达式更快
you can try replacing _ with space using 'str_replace'and then trim spaces them at right side! and then add a _ at the end of string. I dont know a direct way sorry! imo this is faster than regex
您是在正确的轨道上，只是忘记了变量后面的
_。如果您需要锚点 -
\$letters 锚点：
#(\$[az]{1,3}_)_+#和$1字母锚点：
#([az]_)_+#与$1任何锚点：
#((?:^|[^_])_)_+#与$1You are on the right track, just forgot a
_after the variable.If you need an anchor -
\$letters anchor:
#(\$[a-z]{1,3}_)_+#with$1Letter anchor:
#([a-z]_)_+#with$1Any anchor:
#((?:^|[^_])_)_+#with$1