Shell 脚本中的嵌套 If 语句

Question

这是我的脚本：

echo "Name"

read name

if [ "$name" == "abcd" ]; then

 echo "Password"

 read password

 if [ "$password == "pwd" ]; then

  echo "Hello"

 else

  echo "Wrong password"

 fi

else

 echo "wrong username"

fi

这是我运行它时得到的输出：

sh hello.sh

Name

abcd

hello.sh: line 14: unexpected EOF while looking for matching `"'

hello.sh: line 16: syntax error: unexpected end of file

知道这里出了什么问题吗？这可能是一个非常愚蠢的问题，但我在上面浪费了将近一个小时。

Answer 1

if [ "$password == "pwd" ]; then

您在 $password 之前有一个不匹配的 "

Answer 2

您可以使用case。这是一个例子。出于安全原因，您不会想告诉任何人哪个组件出了问题。

echo "Name"
read name
echo "Password"
read password
case "${name}${password}" in
 "abcdpwd" ) 
     echo "hello";;
  *) echo "User or password is wrong";;
esac

Answer 3

在 Shell 脚本中。

if condition
    then
        if condition
        then
            .....
            ..
            do this
        else
            ....
            ..
            do this
        fi
    else
        ...
        .....
        do this
    fi

Answer 4

if [ "$name" == "abcd" ];
then
  echo "Password"
  read password
  if [ "$password" == "pwd" ];
  then
    echo "Hello"
  else
    echo "Wrong password"
  fi
else
  echo "wrong username"
fi