将 NSString(2011-04-18 18:57:47.453000) 转换为 NSDate

发布于 2024-11-02 05:32:49 字数 595 浏览 0 评论 0原文

嘿，伙计们，我搜索了很多，但无法让我的代码工作。

我得到一个字符串形式的日期，格式如下： 2011-04-18 18:57:47.453000

我想将其转换为 NSDate 以计算经过的时间，但我似乎无法正确转换。这就是我正在做的：

NSString *dateString = [entityData objectForKey:@"creation_time"];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss.fff"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:dateString];
[dateFormatter release];

当我打印 dateString 时，我得到：2011-04-18 18:57:47.453000 但打印 dateFromString 给出： (null)

谁能指出我正确的方向？

原文

Hey, guys i searched a lot but cant get my code working.

I am getting a date in form of a string with format like : 2011-04-18 18:57:47.453000

I want to convert this to NSDate to calculate time elapsed, but I cant seem to get the conversion right. here is what i am doing:

NSString *dateString = [entityData objectForKey:@"creation_time"];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss.fff"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:dateString];
[dateFormatter release];

when i print dateString i get : 2011-04-18 18:57:47.453000
but printing dateFromString gives: (null)

Can anyone point me in the right direction?

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没有心的人 2024-11-09 05:32:49

您可能不久前就解决了这个问题...但是：

NSString *dateString = @"2011-04-18 18:57:47.453000";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setTimeZone: [NSTimeZone timeZoneWithAbbreviation:@"GMT"]];
[df setDateFormat:@"yyyy-MM-dd HH:mm:ss.SSSSSS"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [df dateFromString:dateString];
[df release];

可以在位于此处的“日期字段符号表”中找到有关转换日期组件的一些有用信息：

http://unicode.org/reports/tr35/tr35-6.html#Date_Format_Patterns

You probably solved this awhile ago... but:

NSString *dateString = @"2011-04-18 18:57:47.453000";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setTimeZone: [NSTimeZone timeZoneWithAbbreviation:@"GMT"]];
[df setDateFormat:@"yyyy-MM-dd HH:mm:ss.SSSSSS"];
NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [df dateFromString:dateString];
[df release];

Some good information on converting date components can be found in the "Date Field Symbol Table" located here:

http://unicode.org/reports/tr35/tr35-6.html#Date_Format_Patterns

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