代码中的堆栈跟踪
我想知道如何向此代码的堆栈添加跟踪,以将表达式的中缀转换为后缀。
class Node {
public Object data;
public Node next;
public Node () {
data =' '; next = null; }
public Node (Object val) {
data = val; next = null; }
}
public class LinkStack {
private Node top;
public LinkStack() {
top = null; }
public boolean empty(){
return top == null; }
public boolean full(){
return false;
}
public void push(Object e){
Node tmp = new Node(e);
tmp.next = top;
top = tmp;
}
public Object pop(){
Object e = top.data;
top = top.next;
return e;
}
public Object peek(){
Object e = top.data;
return e;
}
public void matching(String x)
{
LinkStack S=new LinkStack();
for(int i=0;i<x.length();i++)
{
char c=x.charAt(i);
if(c=='(')
S.push(c);
else
{
if(c==')')
if(S.empty())
System.out.println("NOT MATCHING !!!");
else
S.pop();
}
}
if(!S.empty())
System.out.println("NOT MATCHING !!!");
else
System.out.println("MATCHING !!!");
}
public void Evaluation(String x)
{
LinkStack S=new LinkStack();
for(int i=0;i<x.length();i++)
{
char c=x.charAt(i);
String s="0"+c;
if(c=='+')
{
int z=Integer.parseInt((String)S.pop())+Integer.parseInt((String)S.pop());
S.push(Integer.toString(z));
}
else if(c=='*')
{
int z=Integer.parseInt((String)S.pop())*Integer.parseInt((String)S.pop());
S.push(Integer.toString(z));
}
else if(c=='/')
{ int u=Integer.parseInt((String)S.pop());
int z=Integer.parseInt((String)S.pop())/u;
S.push(Integer.toString(z));
}
else if(c=='-')
{ int u=Integer.parseInt((String)S.pop());
int z=Integer.parseInt((String)S.pop())-u;
S.push(Integer.toString(z));
}
else
S.push(s);
}
System.out.println("THE POSTFIX = "+x);
System.out.println("THE RESULT = "+S.pop());
}
public void postfix(String x)
{
String output="";
LinkStack S=new LinkStack();
for(int i=0;i<x.length();i++)
{
char c=x.charAt(i);
if(c==('+')||c==('*')||c==('-')||c==('/'))
{while(!S.empty() && priority(S.peek())>= priority(c))
output+=S.pop();
S.push(c);
System.out.println(output);
}
else if(c=='(')
{
S.push(c);
}
else if(c==')')
{
while(!S.peek().equals('('))
output+=S.pop();
S.pop();
System.out.println(output);
}
else
{
output+=c;
System.out.println(output);
}
}
while(!S.empty())
output+=S.pop();
System.out.println("THE INFIX = "+x);
System.out.println("THE POSTFIX = "+output);
}
public int priority(Object x)
{
if(x.equals('+')||x.equals('-'))
return 1;
else if(x.equals('*')||x.equals('/'))
return 2;
else
return 0;
}
public static void main(String args[])
{
LinkStack s=new LinkStack();
s.postfix("x*y–z+(a–c/d)");
System.out.println("------------------------------------------");
s.matching("x*y–z+(a–c/d)");
System.out.println("------------------------------------------");
}
}
I was wondering how I would add a trace to the stack of this code that converts infix to postix for expressions.
class Node {
public Object data;
public Node next;
public Node () {
data =' '; next = null; }
public Node (Object val) {
data = val; next = null; }
}
public class LinkStack {
private Node top;
public LinkStack() {
top = null; }
public boolean empty(){
return top == null; }
public boolean full(){
return false;
}
public void push(Object e){
Node tmp = new Node(e);
tmp.next = top;
top = tmp;
}
public Object pop(){
Object e = top.data;
top = top.next;
return e;
}
public Object peek(){
Object e = top.data;
return e;
}
public void matching(String x)
{
LinkStack S=new LinkStack();
for(int i=0;i<x.length();i++)
{
char c=x.charAt(i);
if(c=='(')
S.push(c);
else
{
if(c==')')
if(S.empty())
System.out.println("NOT MATCHING !!!");
else
S.pop();
}
}
if(!S.empty())
System.out.println("NOT MATCHING !!!");
else
System.out.println("MATCHING !!!");
}
public void Evaluation(String x)
{
LinkStack S=new LinkStack();
for(int i=0;i<x.length();i++)
{
char c=x.charAt(i);
String s="0"+c;
if(c=='+')
{
int z=Integer.parseInt((String)S.pop())+Integer.parseInt((String)S.pop());
S.push(Integer.toString(z));
}
else if(c=='*')
{
int z=Integer.parseInt((String)S.pop())*Integer.parseInt((String)S.pop());
S.push(Integer.toString(z));
}
else if(c=='/')
{ int u=Integer.parseInt((String)S.pop());
int z=Integer.parseInt((String)S.pop())/u;
S.push(Integer.toString(z));
}
else if(c=='-')
{ int u=Integer.parseInt((String)S.pop());
int z=Integer.parseInt((String)S.pop())-u;
S.push(Integer.toString(z));
}
else
S.push(s);
}
System.out.println("THE POSTFIX = "+x);
System.out.println("THE RESULT = "+S.pop());
}
public void postfix(String x)
{
String output="";
LinkStack S=new LinkStack();
for(int i=0;i<x.length();i++)
{
char c=x.charAt(i);
if(c==('+')||c==('*')||c==('-')||c==('/'))
{while(!S.empty() && priority(S.peek())>= priority(c))
output+=S.pop();
S.push(c);
System.out.println(output);
}
else if(c=='(')
{
S.push(c);
}
else if(c==')')
{
while(!S.peek().equals('('))
output+=S.pop();
S.pop();
System.out.println(output);
}
else
{
output+=c;
System.out.println(output);
}
}
while(!S.empty())
output+=S.pop();
System.out.println("THE INFIX = "+x);
System.out.println("THE POSTFIX = "+output);
}
public int priority(Object x)
{
if(x.equals('+')||x.equals('-'))
return 1;
else if(x.equals('*')||x.equals('/'))
return 2;
else
return 0;
}
public static void main(String args[])
{
LinkStack s=new LinkStack();
s.postfix("x*y–z+(a–c/d)");
System.out.println("------------------------------------------");
s.matching("x*y–z+(a–c/d)");
System.out.println("------------------------------------------");
}
}
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对此没有火箭科学的解决方案。
只需在相关位置添加 System.err.println(...) 调用即可。或者,如果您在生产代码中执行此操作(但愿禁止!),您可以使用
Logger
而不是System.err
。(郑重声明,术语“堆栈跟踪”通常表示程序调用堆栈的跟踪,而不是某些特定于应用程序的堆栈数据结构所发生情况的跟踪。您可能需要更仔细地选择术语下次。)
There's no rocket science solution to this.
Just add
System.err.println(...)
calls at the relevant places. Or if you were doing this in production code (heaven forbid!) you might use aLogger
instead ofSystem.err
.(For the record, the term "stack trace" normally means a trace of a program's call stack, not a trace of what happens to some application-specific stack data structure. You might want to choose your terminology a little more carefully next time.)