filesize() stat 函数获取 MP3 文件的 ID3 标签失败

Question

它适用于本地文件，但不适用于外部域。这是我的代码（我从 获得http://www.barattalo.it/2010/02/22/reading-mp3-informations-with-php-id3-tags/）：

<?
function tagReader($file){
$id3v23 = array("TIT2","TALB","TPE1","TRCK","TDRC","TLEN","USLT");
$id3v22 = array("TT2","TAL","TP1","TRK","TYE","TLE","ULT");
$fsize = filesize($file);
$fd = fopen($file,"r");
$tag = fread($fd,$fsize);
$tmp = "";
fclose($fd);
if (substr($tag,0,3) == "ID3") {
    $result['FileName'] = $file;
    $result['TAG'] = substr($tag,0,3);
    $result['Version'] =    hexdec(bin2hex(substr($tag,3,1))).".".hexdec(bin2hex(substr($tag,4,1)));
}
if($result['Version'] == "4.0" || $result['Version'] == "3.0"){
    for ($i=0;$i<count($id3v23);$i++){
        if (strpos($tag,$id3v23[$i].chr(0))!= FALSE){
            $pos = strpos($tag, $id3v23[$i].chr(0));
            $len = hexdec(bin2hex(substr($tag,($pos+5),3)));
            $data = substr($tag, $pos, 10+$len);
            for ($a=0;$a<strlen($data);$a++){
                $char = substr($data,$a,1);
                if($char >= " " && $char <= "~") $tmp.=$char;
            }
            if(substr($tmp,0,4) == "TIT2") $result['Title'] = substr($tmp,4);
            if(substr($tmp,0,4) == "TALB") $result['Album'] = substr($tmp,4);
            if(substr($tmp,0,4) == "TPE1") $result['Author'] = substr($tmp,4);
            if(substr($tmp,0,4) == "TRCK") $result['Track'] = substr($tmp,4);
            if(substr($tmp,0,4) == "TDRC") $result['Year'] = substr($tmp,4);
            if(substr($tmp,0,4) == "TLEN") $result['Length'] = substr($tmp,4);
            if(substr($tmp,0,4) == "USLT") $result['Lyric'] = substr($tmp,7);
            $tmp = "";
        }
    }
}
if($result['Version'] == "2.0"){
    for ($i=0;$i<count($id3v22);$i++){
        if (strpos($tag,$id3v22[$i].chr(0))!= FALSE){
            $pos = strpos($tag, $id3v22[$i].chr(0));
            $len = hexdec(bin2hex(substr($tag,($pos+3),3)));
            $data = substr($tag, $pos, 6+$len);
            for ($a=0;$a<strlen($data);$a++){
                $char = substr($data,$a,1);
                if($char >= " " && $char <= "~") $tmp.=$char;
            }
            if(substr($tmp,0,3) == "TT2") $result['Title'] = substr($tmp,3);
            if(substr($tmp,0,3) == "TAL") $result['Album'] = substr($tmp,3);
            if(substr($tmp,0,3) == "TP1") $result['Author'] = substr($tmp,3);
            if(substr($tmp,0,3) == "TRK") $result['Track'] = substr($tmp,3);
            if(substr($tmp,0,3) == "TYE") $result['Year'] = substr($tmp,3);
            if(substr($tmp,0,3) == "TLE") $result['Lenght'] = substr($tmp,3);
            if(substr($tmp,0,3) == "ULT") $result['Lyric'] = substr($tmp,6);
            $tmp = "";
        }
    }
}
return $result;
}
$song = tagReader("file.mp3");
echo $song[Title];
?>

Answer 1

它仅适用于本地文件。您无法将远程 mp3 文件作为此函数的参数传递，这是毫无意义的。文件使用 fopen() 打开，因此它们必须是本地文件。 filesize() 也是如此。

  $fsize = filesize($file);
  $fd = fopen($file,"r");

您到底想用这个函数加载什么？ “它不适用于外部域”是什么意思？

此行仅适用于与此脚本存储在同一目录中的 file.mp3。

  $song = tagReader("file.mp3");

如果您无法读取本地文件，则应检查该文件的读取权限。

与 filesize() 可能不起作用的原因相同。

建议：您应该对字母数字数组索引使用引号...

  echo $song['Title']; // or 
  echo $song["Title"];

而不是

  echo $song[Title];

“是的，它可能有效”，但您仍然不应该这样做。我建议使用单引号来避免在某些特定情况下评估变量名称（作为数组索引，例如 $array['$index']）。