C# silverlight expression-blend visualstatemanager

编程状态更改在 Silverlight 中不起作用

发布于 2024-11-01 18:44:46 字数 1572 浏览 10 评论 0原文

我试图通过代码使用视觉状态管理器来改变状态。

我正在使用：

Microsoft.Expression.Interactivity.Core.ExtendedVisualStateManager.GoToElementState(this.LayoutRoot, "stateRegistration", true);

但它似乎不想工作，我创建了一个事件处理程序和一个侦听器，但使用该代码时状态没有改变。

谁能帮我一下。

XAML 代码（代码片段）：

<Grid x:Name="LayoutRoot" Width="897" Height="699">
<VisualStateManager.VisualStateGroups>
<VisualState x:Name="stateRegistration">
                    <Storyboard>
                        <DoubleAnimation Duration="0" To="870" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateX)" Storyboard.TargetName="RegisterContent" d:IsOptimized="True"/>
                        <DoubleAnimation Duration="0" To="880" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateX)" Storyboard.TargetName="HomeContent" d:IsOptimized="True"/>
                        <DoubleAnimation Duration="0" To="0" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateX)" Storyboard.TargetName="btnRegRegister" d:IsOptimized="True"/>
                        <DoubleAnimation Duration="0" To="-10" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateY)" Storyboard.TargetName="btnRegRegister" d:IsOptimized="True"/>
                    </Storyboard>
                </VisualState>
            </VisualStateGroup>
        </VisualStateManager.VisualStateGroups>
</Grid>

谢谢。

原文

I'm trying to get states to change with the visual state manager through code.

I am using:

Microsoft.Expression.Interactivity.Core.ExtendedVisualStateManager.GoToElementState(this.LayoutRoot, "stateRegistration", true);

But it doesn't seem to want to work, I have create an event handler and also a listener but it there's no state changed when using that code.

Can anyone help me out.

XAML CODE (Code Snippet):

<Grid x:Name="LayoutRoot" Width="897" Height="699">
<VisualStateManager.VisualStateGroups>
<VisualState x:Name="stateRegistration">
                    <Storyboard>
                        <DoubleAnimation Duration="0" To="870" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateX)" Storyboard.TargetName="RegisterContent" d:IsOptimized="True"/>
                        <DoubleAnimation Duration="0" To="880" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateX)" Storyboard.TargetName="HomeContent" d:IsOptimized="True"/>
                        <DoubleAnimation Duration="0" To="0" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateX)" Storyboard.TargetName="btnRegRegister" d:IsOptimized="True"/>
                        <DoubleAnimation Duration="0" To="-10" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateY)" Storyboard.TargetName="btnRegRegister" d:IsOptimized="True"/>
                    </Storyboard>
                </VisualState>
            </VisualStateGroup>
        </VisualStateManager.VisualStateGroups>
</Grid>

Thanks.

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善良天后 2024-11-08 18:44:46

VisualStateManager 有一个奇怪的行为：它的状态必须不在控件中，而是在子控件中。

这意味着，应使用 this 参数而不是 this.LayoutRoot 参数调用 GoToState 方法，但状态组的定义必须是位于 Grid 内部：

VisualStateManager.GoToState(this, "stateRegistration", true);

我不知道从哪里获取 ExtendedVisualStateManager 类，因此我使用默认的类。

此外，如果状态故事板的任何动画失败 - 所有动画都将被取消。因此，尝试使用两个动画的代码示例，它一定可以工作：

<Grid x:Name="LayoutRoot" Width="897" Height="699">
    <VisualStateManager.VisualStateGroups>
        <VisualStateGroup>
            <VisualState x:Name="stateRegistration">
                <Storyboard>
                    <DoubleAnimation Duration="0" To="0" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateX)" Storyboard.TargetName="btnRegRegister" d:IsOptimized="True"/>
                    <DoubleAnimation Duration="0" To="-10" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateY)" Storyboard.TargetName="btnRegRegister" d:IsOptimized="True"/>
                </Storyboard>
            </VisualState>
        </VisualStateGroup>
    </VisualStateManager.VisualStateGroups>
    <Button x:Name="btnRegRegister" Content="Some button" Click="btnRegRegister_Click" VerticalAlignment="Center" HorizontalAlignment="Center">
        <Button.RenderTransform>
            <CompositeTransform TranslateX="0" TranslateY="0" />
        </Button.RenderTransform>
    </Button>
</Grid>

There is strange behavior with the VisualStateManager: its states must be situated not in the control, but in the child control.

It means, that the GoToState method should be called with the this parameter instead of the this.LayoutRoot parameter, but definitions of state groups must be situated inside the Grid:

VisualStateManager.GoToState(this, "stateRegistration", true);

I don't know where to get the ExtendedVisualStateManager class so I use the default one.

Also if any animation of the state storyboard fails - all animations are cancelled. So try this code sample with two animations, it must work:

<Grid x:Name="LayoutRoot" Width="897" Height="699">
    <VisualStateManager.VisualStateGroups>
        <VisualStateGroup>
            <VisualState x:Name="stateRegistration">
                <Storyboard>
                    <DoubleAnimation Duration="0" To="0" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateX)" Storyboard.TargetName="btnRegRegister" d:IsOptimized="True"/>
                    <DoubleAnimation Duration="0" To="-10" Storyboard.TargetProperty="(UIElement.RenderTransform).(CompositeTransform.TranslateY)" Storyboard.TargetName="btnRegRegister" d:IsOptimized="True"/>
                </Storyboard>
            </VisualState>
        </VisualStateGroup>
    </VisualStateManager.VisualStateGroups>
    <Button x:Name="btnRegRegister" Content="Some button" Click="btnRegRegister_Click" VerticalAlignment="Center" HorizontalAlignment="Center">
        <Button.RenderTransform>
            <CompositeTransform TranslateX="0" TranslateY="0" />
        </Button.RenderTransform>
    </Button>
</Grid>

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