绝对uri：http://java.sun.com/jsp/jstl/core无法解析

Question

我选择了一个新创建的 maven webapp 项目，并想用它来做最简单的 mvc 应用程序。我的环境看起来像这样：

<artifactId>spring-core</artifactId>
        <artifactId>spring-test</artifactId>
        <artifactId>spring-beans</artifactId>
        <artifactId>spring-context</artifactId>
        <artifactId>spring-aop</artifactId>
        <artifactId>spring-context-support</artifactId>
        <artifactId>spring-tx</artifactId>
        <artifactId>spring-orm</artifactId>  
        <artifactId>spring-web</artifactId>
        <artifactId>spring-webmvc</artifactId>
        <artifactId>spring-asm</artifactId>
        <artifactId>log4j</artifactId>
        <artifactId>hibernate-core</artifactId>
        <artifactId>hibernate-cglib-repack</artifactId>
        <artifactId>hsqldb</artifactId>

        <!-- particular arears-->
         <dependency>
           <groupId>taglibs</groupId>
           <artifactId>standard</artifactId>
           <scope>provided</scope>
        </dependency>
        <dependency>
           <groupId>javax.servlet</groupId>
           <artifactId>servlet-api</artifactId>
           <scope>provided</scope>
        </dependency>
        <!-- -->

       <spring.version>3.0.5.RELEASE</spring.version>
       <hibernate.version>3.6.1.Final</hibernate.version>
       <hibernate-cglig-repack.version>2.1_3</hibernate-cglig-repack.version>
       <log4j.version>1.2.14</log4j.version>
       <javax-servlet-api.version>2.5</javax-servlet-api.version>
       <hsqldb.version>1.8.0.10</hsqldb.version>
       <mysql-connector.version>5.1.6</mysql-connector.version>
       <slf4j-log4j12.version>1.5.2</slf4j-log4j12.version>
       <slf4j-api.version>1.5.8</slf4j-api.version>
       <javaassist.version>3.7.ga</javaassist.version>
       <taglibs.version>1.1.2</taglibs.version>


        <plugins>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-compiler-plugin</artifactId>
            <version>2.0.2</version>
            <configuration>
                <source>1.6</source>
                <target>1.6</target>
            </configuration>
        </plugin>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-war-plugin</artifactId>
            <version>2.1-beta-1</version>
            <configuration>
                <failOnMissingWebXml>false</failOnMissingWebXml>
            </configuration>
        </plugin>
    </plugins>
    <finalName>admin-webapp</finalName>
</build>
<profiles>
    <profile>
        <id>endorsed</id>
        <activation>
            <property>
                <name>sun.boot.class.path</name>
            </property>
        </activation>
        <build>
            <plugins>
                <plugin>
                    <groupId>org.apache.maven.plugins</groupId>
                    <artifactId>maven-compiler-plugin</artifactId>
                    <version>2.0.2</version>
                    <configuration>
                        <!-- javaee6 contains upgrades of APIs contained within the JDK itself.
                             As such these need to be placed on the bootclasspath, rather than classpath of the
                             compiler.
                             If you don't make use of these new updated API, you can delete the profile.
                             On non-SUN jdk, you will need to create a similar profile for your jdk, with the similar property as sun.boot.class.path in Sun's JDK.-->
                        <compilerArguments>
                            <bootclasspath>${settings.localRepository}/javax/javaee-endorsed-api/6.0/javaee-endorsed-api-6.0.jar${path.separator}${sun.boot.class.path}</bootclasspath>
                        </compilerArguments>
                    </configuration>
                    <dependencies>
                        <dependency>
                            <groupId>javax</groupId>
                            <artifactId>javaee-endorsed-api</artifactId>
                            <version>6.0</version>
                        </dependency>
                    </dependencies>
                </plugin>
            </plugins>
        </build>
    </profile>
</profiles>
<properties>
    <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
    <netbeans.hint.deploy.server>Tomcat60</netbeans.hint.deploy.server>
    <tomcat.home>${env.CATALINA_HOME}</tomcat.home>
    <web.context>${project.artifactId}</web.context>
</properties>

我的 applicationContext 就像这样简单：

<context:component-scan base-package="com.personal.springtest.admin.webapp" />
<mvc:annotation-driven />

web.xml 就像这样简单：

<web-app xmlns="http://java.sun.com/xml/ns/javaee"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
 version="3.0">
<session-config>
    <session-timeout>
        30
    </session-timeout>
</session-config>

<servlet>
    <servlet-name>iwadminservlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/project-admin-webapp-config.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

   <servlet-mapping>
    <servlet-name>iwadminservlet</servlet-name>
    <url-pattern>/</url-pattern>
   </servlet-mapping>
</web-app>

我的控制器就像这样：

@Controller
public class HomeController {

   @RequestMapping(value="/")
   public String Home(){
    System.out.print("THIS IS a demo mvc, i think i like it");
    // this is temporary, will use viewresolver when everything clears up
    return "/views/home.jsp";
   }

}

我的观点是：

<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<%@ page session="false" %>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"    "http://www.w3.org/TR/html4/loose.dtd">
<html>
   <head>
      <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
      <title>JSP Page</title>
   </head>
   <body>
      <h1>Hello World!</h1>
   </body>
</html>

我得到的错误是

org.apache.jasper.JasperException：绝对 uri：http://java.sun .com/jsp/jstl/core 无法在 web.xml 或使用此应用程序部署的 jar 文件中解析

问题 1：我想知道这是否是由于我正在使用的版本造成的，我认为我读过一些有关 tomcat 中支持的版本的内容，并且使用了 java ee 版本。并没有真正从中找到解决我的问题的方法。我该如何解决这个问题？

问题 2：在此错误之前，我遇到了代码 400，因为我没有正确地将其指向 views/home.jsp，但我确实注意到，当我在netbeans，它会打开浏览器，网址为：http://localhot:8080/，而我正在期待http://localhost:8080/admin-webapp/ admin-webapp 是我的战争的名称。我认为这是一个问题并且希望解决它。

Answer 1

您需要 JSTL 实现：

<dependency>
    <groupId>javax.servlet</groupId>
    <artifactId>jstl</artifactId>
    <version>1.2</version>
</dependency>

或者如果您手动包含 JSTL jar：

<dependency>
    <groupId>javax.servlet</groupId>
    <artifactId>jstl</artifactId>
    <version>1.2</version>
    <scope>provided</scope>
</dependency>

Answer 2

1. 从此处下载 JSTL API 和 JSTL 实现

2. 添加此指令：< ;%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>

3. 将 JAR 文件粘贴到 WEB-INF/lib 文件夹中。这应该有效。 （它
   为我工作。）