xmlrpc 服务器问题

Question

我使用 xmlrpc 服务器运行简单的示例，然后按键盘上的 Ctrl-C :)。

from SimpleXMLRPCServer import SimpleXMLRPCServer
from time import sleep
import threading,time

class Test(threading.Thread):
    def __init__(self):
        threading.Thread.__init__(self)
        self.test1 = 0
    def test(self):
        return self.test1

    def run(self):
        while(1):
            time.sleep(1)
            self.test1 = self.test1 + 1

ts = Test()
ts.start()
server =  SimpleXMLRPCServer(("localhost",8888))
server.register_instance(ts)
server.serve_forever()

按下键盘后出现错误：

  File "/usr/lib/python2.7/SocketServer.py", line 225, in serve_forever
    r, w, e = select.select([self], [], [], poll_interval)
KeyboardInterrupt

客户端

 
from xmlrpclib import ServerProxy
r=ServerProxy("http://localhost:8888")
print r.test()
 

waiting connect without error or warning. How to break connection in this case ? Maybe this example is not correct ?

Answer 1

使用超时：

为 xmlrpclib.ServerProxy 设置超时

编辑

此处链接的答案与 Python 2.7 不兼容。以下是修改后的有效代码（在 W7/ActivePython 2.7 上测试）：

import xmlrpclib
import httplib

class TimeoutHTTPConnection(httplib.HTTPConnection):

    def __init__(self,host,timeout=10):
        httplib.HTTPConnection.__init__(self,host,timeout=timeout)
        self.set_debuglevel(99)
        #self.sock.settimeout(timeout)

"""
class TimeoutHTTP(httplib.HTTP):
    _connection_class = TimeoutHTTPConnection
    def set_timeout(self, timeout):
        self._conn.timeout = timeout
"""

class TimeoutTransport(xmlrpclib.Transport):
    def __init__(self, timeout=10, *l, **kw):
        xmlrpclib.Transport.__init__(self,*l,**kw)
        self.timeout=timeout

    def make_connection(self, host):
        conn = TimeoutHTTPConnection(host,self.timeout)
        return conn

class TimeoutServerProxy(xmlrpclib.ServerProxy):
    def __init__(self,uri,timeout=10,*l,**kw):
        kw['transport']=TimeoutTransport(timeout=timeout, use_datetime=kw.get('use_datetime',0))
        xmlrpclib.ServerProxy.__init__(self,uri,*l,**kw)

if __name__ == "__main__":
    s=TimeoutServerProxy('http://127.0.0.1:8888',timeout=2)
    print s.test()

Answer 2

让您的 Test 实例成为守护进程，以便在主线程退出时退出：

ts = Test()
ts.setDaemon(True)
ts.start()

问题是为什么您需要将线程注册为 XML-RPC 处理程序。