mongoid、embedy_many、simple_form

Question

我正在寻找一种方法来管理表单中的多个嵌入对象。

Bowsersenior

Formtastic with Mongoid嵌入关系

找到了formtastic的解决方案，但我无法对 simple_form formattastic 执行相同操作

：

= semantic_form_for @team do |form|
  = @team.players.each do |player|
    = form.inputs :for => [:players, player] do |player_form|
      = player_form.input :name

最好的问候

示例

class Team
  include Mongoid::Document
  field :name, :type => String
  embeds_many :players
end

class Player
  include Mongoid::Document
  embedded_in :team, :inverse_of => :players
  field :name, :type => String
  field :active, :type=> Boolean # checkboxes
end

Answer 1

不确定这是否有效，但您可能想尝试这样的操作：

= simple_form_for @team do |form|
  = f.input :name
  = f.simple_fields_for @team.players do |player_form|
    = player_form.input :name

请记住，您必须在表单显示之前在团队中创建一个新玩家。
在你的控制器（控制器）中：

def new
  @team = Team.new
  8.times { @team.players.new } #for 8 players
end