“无法解析的日期：1302828677828”尝试使用 Gson 反序列化从服务器收到的毫秒格式日期

Question

经过 4 个小时不停地尝试解决问题后，我决定在这里询问是否有人可以帮助我。

问题是我的 Android 客户端尝试反序列化从服务器接收的数据时抛出“无法解析：1302828677828”异常。

我想知道是否可以使用 Gson 反序列化毫秒格式的日期。

Answer 1

阿方索评论：

最后我得到了解决方案：

// 创建 json 对象来管理接收到的信息 
GsonBuilder 构建器 = new GsonBuilder(); 

// 注册一个适配器来将日期类型管理为长值 
builder.registerTypeAdapter(Date.class, new JsonDeserializer() { 
   公共日期反序列化（JsonElement json，类型typeOfT，JsonDeserializationContext上下文）抛出JsonParseException {
      返回新日期(json.getAsJsonPrimitive().getAsLong()); 
   } 
});

Gson gson = builder.create();

Answer 2

我基于 GSON 默认 DateTypeAdapter 编写了一个改进的 DateTypeAdapter，它支持默认日期格式和时间戳（长）格式。

import com.google.gson.Gson;
import com.google.gson.JsonSyntaxException;
import com.google.gson.TypeAdapter;
import com.google.gson.TypeAdapterFactory;
import com.google.gson.reflect.TypeToken;
import com.google.gson.stream.JsonReader;
import com.google.gson.stream.JsonToken;
import com.google.gson.stream.JsonWriter;

import java.io.IOException;
import java.text.DateFormat;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Locale;
import java.util.TimeZone;

public final class ImprovedDateTypeAdapter extends TypeAdapter<Date> {

    public static final TypeAdapterFactory FACTORY = new TypeAdapterFactory() {

        public <T> TypeAdapter<T> create(Gson gson, TypeToken<T> typeToken) {

            @SuppressWarnings("unchecked")
            TypeAdapter<T> typeAdapter = (TypeAdapter<T>) ((typeToken.getRawType() == Date.class) ? new ImprovedDateTypeAdapter()
                    : null);
            return typeAdapter;
        }
    };
    private final DateFormat enUsFormat;
    private final DateFormat localFormat;
    private final DateFormat iso8601Format;

    public ImprovedDateTypeAdapter() {
        this.enUsFormat = DateFormat.getDateTimeInstance(2, 2, Locale.US);

        this.localFormat = DateFormat.getDateTimeInstance(2, 2);

        this.iso8601Format = buildIso8601Format();
    }

    private static DateFormat buildIso8601Format() {
        DateFormat iso8601Format = new SimpleDateFormat(
                "yyyy-MM-dd'T'HH:mm:ss'Z'", Locale.US);
        iso8601Format.setTimeZone(TimeZone.getTimeZone("UTC"));
        return iso8601Format;
    }

    public Date read(JsonReader in) throws IOException {
        if (in.peek() == JsonToken.NULL) {
            in.nextNull();
            return null;
        }
        return deserializeToDate(in.nextString());
    }

    private synchronized Date deserializeToDate(String json) {
        try {

            return new Date(Long.parseLong(json));
        } catch (Exception e) {

            try {

                return this.localFormat.parse(json);
            } catch (ParseException e1) {

                try {

                    return this.enUsFormat.parse(json);
                } catch (ParseException e2) {

                    try {

                        return this.iso8601Format.parse(json);
                    } catch (ParseException e3) {

                        throw new JsonSyntaxException(json, e3);
                    }
                }
            }
        }
    }

    public synchronized void write(JsonWriter out, Date value)
            throws IOException {
        if (value == null) {
            out.nullValue();
            return;
        }
        String dateFormatAsString = this.enUsFormat.format(value);
        out.value(dateFormatAsString);
    }
}

使用方法：

// Creates the json object which will manage the information received 
GsonBuilder builder = new GsonBuilder(); 

// Register an adapter to manage the date types as long values 
builder.registerTypeAdapter(Date.class, new ImprovedDateTypeAdapter());

Gson gson = builder.create();

Answer 3

JsonSerializer<Date> serializer= new JsonSerializer<Date>() {
  @Override
  public JsonElement serialize(Date src, Type typeOfSrc, JsonSerializationContext 
             context) {
    return src == null ? null : new JsonPrimitive(src.getTime());
  }
};

JsonDeserializer<Date> deserializer= new JsonDeserializer<Date>() {
  @Override
  public Date deserialize(JsonElement json, Type typeOfT,
       JsonDeserializationContext context) throws JsonParseException {
    return json == null ? null : new Date(json.getAsLong());
  }
};

Gson gson = new GsonBuilder()
   .registerTypeAdapter(Date.class, serializer)
   .registerTypeAdapter(Date.class, deserializer).create();

Answer 4

使用下面的代码片段在处理 JSON 时将毫秒转换为日期。

    GsonBuilder gsonBuilder = new GsonBuilder();
    // Adapter to convert long values to date types
    gsonBuilder.registerTypeAdapter(Date.class, new JsonDeserializer<Date>() {
        public Date deserialize(JsonElement jsonElement, Type typeOfObj, JsonDeserializationContext context)
               throws JsonParseException {
                   //Converting milliseconds to current Date. (instead of 1970)
                return new Date(jsonElement.getAsLong() * 1000);
            }
        });
    Gson gson = gsonBuilder.setPrettyPrinting().create();

Answer 5

当我尝试使用 Rest client 反序列化 DateTime 字段时，我遇到了同样的问题href="http://androidannotations.org/" rel="nofollow">Android 注释 库。
作为一个解决方案，我创建了自定义 GsonHttpMessageConverter

public class CustomGsonHttpMessageConverter extends GsonHttpMessageConverter {

    public CustomGsonHttpMessageConverter() {
        // Creates the json object which will manage the information received
        GsonBuilder builder = new GsonBuilder();

        // Register an adapter to manage the date types as long values
        builder.registerTypeAdapter(Date.class, new JsonDeserializer<Date>() {
            public Date deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
                return new Date(json.getAsJsonPrimitive().getAsLong());
            }
        });

        setGson(builder.create());
    }
}

并在其余客户端中定义它，

@Rest(rootUrl = "http://192.168.1.1:8080", converters = {CustomGsonHttpMessageConverter.class})
public interface RestClient extends RestClientErrorHandling {
...

我希望它会有所帮助

Answer 6

由于某种原因，我在 Intellij 中使用匿名类使用上述代码时出现编译错误； lambda 对我有用：

private static Gson buildGson(){
    // Deserialize longs as Dates
    final JsonDeserializer<Date> dateDeserializer = (json, type, context) -> json == null ? null : new Date(json.getAsLong());
    return new GsonBuilder().registerTypeAdapter(Date.class, dateDeserializer).create();
}

Answer 7

    
        import com.google.gson.Gson;
        import com.google.gson.GsonBuilder;
        import com.google.gson.JsonDeserializer;
        import java.sql.Timestamp;    
        
        
        Gson gson = new GsonBuilder().registerTypeAdapter(Timestamp.class, (JsonDeserializer) (json, typeOfT, context) -> {
                            return new Timestamp(json.getAsLong());
                        }).create();