从 Mockito 模拟中抛出异常

发布于 2024-11-01 05:46:23 字数 1057 浏览 1 评论 0原文

有些东西告诉我我做错了什么......它不应该这么难。

我有一个依赖于某些内部类的类。我通过受保护的方法创建该内部，以便我可以在测试中覆盖它以提供模拟。我知道要让 Mockito 模拟对象从 void 方法抛出异常，我必须使用 doThrow。

但我的问题是编译器抱怨对 Mockito.doThrow() 的调用抛出 RuntimeException...所以我必须在设置模拟的方法中添加一个 throws 子句。这是 Mockito 本身的错误吗？ doThrow 正在声明将来应该发生的事情，但不是在模拟设置期间发生。

我的 OuterClass 看起来像...

public class OuterClass {
  protected InnerClass inner;
  protected void createInner() { inner = new InnerClass(); }
  protected doSomething() {
    try {
      inner.go();
    } catch (RuntimeException re) {
      throw new MyException("computer has caught fire");
    }
  }
}

而我的测试代码看起来像...

@Test(expected = MyException.class)
public void testSomething() {
  OuterClass outer = new TestOuterClass();
  outer.doSomething();
}

public static class TestOuterClass extends OuterClass {
  @Override
  public void createInner() {
    InnerClass mock = Mockito.mock(InnerClass.mock);
    Mockito.doThrow(new RuntimeException("test")).when(mock).go();  // PROBLEM
    inner = mock;
  }
}

原文

Something tells me I'm doing something wrong...it shouldn't be this hard.

I have a class that relies on some inner class. I'm creating that inner through a protected method so that I can override that in a test to provide a mock. I understand that to get a Mockito mock object to throw an exception from a void method, I have to use doThrow.

But my problem is that the compiler complains that the call to Mockito.doThrow() is throwing RuntimeException...so then I have to add a throws clause to the method setting up the mock. Is that a bug in Mockito itself? doThrow is declaring something that should happen in the future, but not during the setup of the mock.

My OuterClass looks like...

public class OuterClass {
  protected InnerClass inner;
  protected void createInner() { inner = new InnerClass(); }
  protected doSomething() {
    try {
      inner.go();
    } catch (RuntimeException re) {
      throw new MyException("computer has caught fire");
    }
  }
}

And my test code looks like...

@Test(expected = MyException.class)
public void testSomething() {
  OuterClass outer = new TestOuterClass();
  outer.doSomething();
}

public static class TestOuterClass extends OuterClass {
  @Override
  public void createInner() {
    InnerClass mock = Mockito.mock(InnerClass.mock);
    Mockito.doThrow(new RuntimeException("test")).when(mock).go();  // PROBLEM
    inner = mock;
  }
}

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逆光下的微笑 2024-11-08 05:46:23

请您检查一下编译器是否真的在抱怨 RuntimeException ？

关于 RuntimeException 的问题是，它在编译时应该无关紧要。我怀疑编译器实际上是在抱怨 MyException - 我认为这是编译器注意到的检查异常，它是由 doSomething() 方法抛出的。您应该能够简单地将 throws MyException 添加到测试方法，然后测试运行程序将捕获该方法。正如预期的那样，测试运行程序将通过。