列表框在不同行中显示一个属性

发布于 2024-10-31 19:06:54 字数 683 浏览 0 评论 0原文

我使用以下代码将 ListBox 绑定到列表（即列表）并设置绑定 Path=Name。但列表框仅显示一个字母按行划分的名称。就像如果名称是 JOHN，列表框第 1 行显示“J”，第 2 行显示“O”，第 3 行显示“H”，第 4 行显示“N”。这是代码。

Xaml

<ListBox Height="Auto" ItemsSource="{Binding Path=Name}" HorizontalAlignment="Stretch" Margin="0,80,0,0" Name="ledgerListView" VerticalAlignment="Stretch" Width="200" KeyDown="ledgerListView_KeyDown" MouseDoubleClick="ledgerListView_MouseDoubleClick" IsSynchronizedWithCurrentItem="True" />

代码隐藏

List<Ledgers> ledgers = new List<Ledgers>();
        ledgers = DAL_Ledgers.LoadLedgers();
        this.DataContext = ledgers;

原文

I am using the following code for binding ListBox to a list i.e. List and set the binding Path=Name. But the list box shows just the one name with letter divided in rows. Like if a Name is JOHN, the list box row 1 shows "J", row 2 shows "O", row 3 shows "H", row 4 shows "N". Here's the code.

Xaml

<ListBox Height="Auto" ItemsSource="{Binding Path=Name}" HorizontalAlignment="Stretch" Margin="0,80,0,0" Name="ledgerListView" VerticalAlignment="Stretch" Width="200" KeyDown="ledgerListView_KeyDown" MouseDoubleClick="ledgerListView_MouseDoubleClick" IsSynchronizedWithCurrentItem="True" />

Code-Behind

List<Ledgers> ledgers = new List<Ledgers>();
        ledgers = DAL_Ledgers.LoadLedgers();
        this.DataContext = ledgers;

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难如初 2024-11-07 19:06:54

ItemsSource 属性需要绑定到要从中生成列表框项目的源集合。在本例中，这只是 DataContext。要显示每个项目的名称，您可以将 DataTemplate 应用到包含要为每个项目显示的内容的 ItemTemplate 属性，或者对于像这样的简单情况，只需使用 DisplayMemberPath 指定 Name 属性。

<ListBox ItemsSource="{Binding}" DisplayMemberPath="Name" x:Name="ledgerListView"/>

The ItemsSource property needs to be bound to the source collection that you want to generate the list box's items from. In this case that would just be the DataContext. To show the name for each item you can either apply a DataTemplate to the ItemTemplate property containing what you want to show for each item, or for a simple case like this just use the DisplayMemberPath to specify the Name property.

<ListBox ItemsSource="{Binding}" DisplayMemberPath="Name" x:Name="ledgerListView"/>

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贱贱哒 2024-11-07 19:06:54

看起来你绑定到了错误的东西......如果你使用它是否有效：

<ListBox ItemsSource="{Binding}" ...>
  <ListBox.ItemTemplate>
    <DataTemplate>
      <sdk:Label Content="{Binding Path=Name}" />
    </DataTemplate>
  </ListBox.ItemTemplate>
</ListBox>

It looks like you're binding to the wrong thing... Does it work if you use:

<ListBox ItemsSource="{Binding}" ...>
  <ListBox.ItemTemplate>
    <DataTemplate>
      <sdk:Label Content="{Binding Path=Name}" />
    </DataTemplate>
  </ListBox.ItemTemplate>
</ListBox>

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