快速搜索Tmemo行的方法

发布于 2024-10-31 17:00:39 字数 495 浏览 4 评论 0原文

我的表单上有一个 TMemo，允许用户输入项目列表。人们可以在这里输入许多项目。当他们单击“保存”时，会检查 TMemo 的内容，然后将其添加到数据库中。

我在 TStringList 中有第二个列表，我循环检查它的任何项目是否包含在 TMemo 中。

简而言之，它看起来像这样

....
//slItems = TStringList
//mItems = TMemo
for i := slItems.Count -1 downto 0 do
begin
  if mItems.Lines.IndexOf(slItems[i]) = -1 then
    slItems[i].Delete;
end;
----

所以 stringlist 循环，检查它是否存在于备忘录中，如果不存在从列表中删除。

然而，当有 200 多个项目时，速度开始减慢很多，而当项目超过 1000 时，情况会变得非常糟糕。

搜索 TMemo 最快的方法是什么？

原文

I have a TMemo on a form which allows users to enter a list of items. People can enter many items here. When they click Save the contents of the TMemo is checked and then added to the database.

I have a second list in a TStringList which I loop over and check to see if any of it's items are contained in the TMemo.

In a nut shell it looks like this

....
//slItems = TStringList
//mItems = TMemo
for i := slItems.Count -1 downto 0 do
begin
  if mItems.Lines.IndexOf(slItems[i]) = -1 then
    slItems[i].Delete;
end;
----

So stringlist looped, check to see if it exists in memo, if not delete from list.

However, with 200+ items this is starting to slow down a lot, and with 1000 it gets real bad.

Whats the fastest way to search a TMemo?

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流心雨 2024-11-07 17:00:39

将所有 TMemo 读入本地 TStringList 并从中进行工作。每次访问 TMemo.Lines 时，您都依赖 Windows 消息传递来与 Windows 提供的多行文本框进行对话。除了高效之外什么都没有！

....
//slItems = TStringList
//mItems = TMemo
//L = TStringList
L.Text := mItems.Text; // edited per David's suggestion.
L.Sorted := True; // per Uwe Raabe's suggestion.
for i := slItems.Count -1 downto 0 do
begin
  if L.IndexOf(slItems[i]) = -1 then
    slItems[i].Delete;
end;
----

Read all of TMemo into a local TStringList and work from that. Every time you're accessing TMemo.Lines you're relying on Windows messaging to talk to the windows-provided multi line text box. Anything but efficient!

....
//slItems = TStringList
//mItems = TMemo
//L = TStringList
L.Text := mItems.Text; // edited per David's suggestion.
L.Sorted := True; // per Uwe Raabe's suggestion.
for i := slItems.Count -1 downto 0 do
begin
  if L.IndexOf(slItems[i]) = -1 then
    slItems[i].Delete;
end;
----

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