ack regex：按顺序匹配同一行中的两个单词
我想在文件中查找按顺序包含两个单词 word_1 和 word_2 的行，例如下面的 Line A 中，但不是这样在 Line B 或 Line C 中：
Line A: ... word_1 .... word_2 ....
Line B: ... word_1 ....
Line C: ... word_2 ....
我尝试
$ack '*word_1*word_2'
$ack '(word_1)+*(word_2)+'
过在正则表达式的开头附加相同的命令 ^ （试图遵循Perl 正则表达式语法）。
这些命令都没有返回我感兴趣的文件或行。
我做错了什么？
谢谢！
I would like to find lines in files that include two words, word_1 and word_2 in order, such as in Line A below, but not as in Line B or Line C:
Line A: ... word_1 .... word_2 ....
Line B: ... word_1 ....
Line C: ... word_2 ....
I have tried
$ack '*word_1*word_2'
$ack '(word_1)+*(word_2)+'
and the same commands with ^ appended at the beginning of the regex (in an attempt to follow the Perl regex syntax).
None of these commands return the files or the lines I am interested in.
What am I doing wrong?
Thanks!
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您想要查找
word_1，后跟任意次数的任何内容，最后是word_2。那应该是你似乎正在使用
*因为它经常在命令行搜索中使用，但在正则表达式中它是前面字符的量词，意味着匹配它至少 0 次。例如，正则表达式a*将匹配 0 个或多个a，而正则表达式a+将匹配至少一个a< /代码>。表示“匹配任何内容”的正则表达式元字符是
.，因此.*表示“匹配任何内容，任意次数。请参阅 perlrequick 有关该主题的简要介绍。You want to find
word_1, followed by anything, any number of times, followed byword_2. That should beYou seem to be using
*as it is often used in command line searches, but in regexes is it a quantifier for the preceding character, meaning match it at least 0 times. For example, the regexa*would match 0 or moreas, whereas the regexa+would match at least onea.The regex metacharacter meaning "match anything" is
., so.*means "match anything, any number of times. See perlrequick for a brief introduction on the topic.