iPhone UISwitch 与另一个 UISwitch 发生反应

发布于 2024-10-31 15:03:55 字数 534 浏览 6 评论 0原文

我已经阅读了有关 UISwitches 的所有内容，但我似乎无法在我的情况下弄清楚它们。我有 2 个 UISwitch。为了使我的代码正常工作，只能打开其中之一。我将如何实现这个目标？

到目前为止，我已经尝试过...

MyClass.h

-(IBAction)sufSwitchChanged:(id)sender;

MyClass.m

-(IBAction)preSwitchChanged:(id)sender {
UISwitch *whichSwitch = (UISwitch *)sender;
BOOL setting = whichSwitch.isOn;
[newsPre setOn:setting animated:YES];
[techPre setOn:setting animated:YES];
}

....它有效，但它使两个开关都打开或关闭。我只需要弄清楚如何防止它们同时打开。

原文

I've read all about UISwitches already but I cannot seem to figure them out in my situation.
I have 2 UISwitches. In order for my code to work only one of them can be ON. How would I accomplish this?

So far i've tried...

MyClass.h

-(IBAction)sufSwitchChanged:(id)sender;

MyClass.m

-(IBAction)preSwitchChanged:(id)sender {
UISwitch *whichSwitch = (UISwitch *)sender;
BOOL setting = whichSwitch.isOn;
[newsPre setOn:setting animated:YES];
[techPre setOn:setting animated:YES];
}

....which worked but it made both switches ON or OFF. I just need to figure out how to prevent them from both being ON at the same time.

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梦归所梦 2024-11-07 15:03:55

注册两个 UISwitch 以观察另一个开关的 UIControlEventValueChanged 通知。类似于：

- (void)viewDidLoad { // or whatever method is appropriate
    UISwitch *a = <# initialize a #>;
    UISwitch *b = <# initialize b #>;

    [a addTarget:self action:@selector(toggleB:)   
         forControlEvents:UIControlEventValueChanged]; 

    [b addTarget:self action:@selector(toggleA:)   
         forControlEvents:UIControlEventValueChanged]; 
}

- (IBAction)toggleA:(id)sender {
    [b setOn:NO animated:YES];
}

- (IBAction)toggleB:(id)sender {
    [a setOn:NO animated:YES];
}

您还可以在 Interface Builder 中设置这种关系。

Register both UISwitches to observe UIControlEventValueChanged notifications against the the other switch. Something like:

- (void)viewDidLoad { // or whatever method is appropriate
    UISwitch *a = <# initialize a #>;
    UISwitch *b = <# initialize b #>;

    [a addTarget:self action:@selector(toggleB:)   
         forControlEvents:UIControlEventValueChanged]; 

    [b addTarget:self action:@selector(toggleA:)   
         forControlEvents:UIControlEventValueChanged]; 
}

- (IBAction)toggleA:(id)sender {
    [b setOn:NO animated:YES];
}

- (IBAction)toggleB:(id)sender {
    [a setOn:NO animated:YES];
}

You can also set this relationship up in Interface Builder.

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假装不在乎 2024-11-07 15:03:55

请注意您如何将两个开关设置为相同的值：

[newsPre setOn:setting animated:YES];
[techPre setOn:setting animated:YES];

您想要检查哪一个是发送者，然后将另一个设置为与设置相反的值。为此，您需要在每个开关上设置一个标签，或者可能对其进行子类化。有关检测哪个交换机是哪个交换机的更多信息，请参阅这篇文章，其中有一些很好的信息。

Notice how you are setting both switches to the same value here:

[newsPre setOn:setting animated:YES];
[techPre setOn:setting animated:YES];

You want to check which one is the sender and then set the other one to the opposite of setting. To do so, you will need to set a tag on each switch, or perhaps subclass it. For more information on detecting which switch is which, see this post, which has some good information.

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