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c# 填充前导八位字节

发布于 2024-10-31 13:12:07 字数 125 浏览 1 评论 0原文

我的指数是 3 个字节长。现在我需要它是 4 个字节。我找到了可以填充前导八位字节的地方..但我不知道该怎么做..所以有人可以帮助我吗？

示例输入：我现在拥有的指数是 65537，然后是 int 字节 01 00 01。

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掩耳倾听 2024-11-07 13:12:07

假设您只想用零填充它，创建一个新的四字节数组并将现有的复制到其中：（

byte[] newArray = new byte[4];
// Copy bytes 0, 1, 2 of oldArray into 1, 2, 3 of newArray.
Array.Copy(oldArray, 0, newArray, 1, 3);

您也可以通过三个赋值手动执行此操作；对于这种情况，这可能更简单，但扩展性不好（

如果您发现需要在末尾而不是开头进行填充，请将“1”更改为“0”...或在其中使用 Array.Resize 案件。

Assuming you just want to pad it with zeroes, create a new four byte array and copy the existing one into it:

byte[] newArray = new byte[4];
// Copy bytes 0, 1, 2 of oldArray into 1, 2, 3 of newArray.
Array.Copy(oldArray, 0, newArray, 1, 3);

(You can do this manually with three assignments as well; that's potentially simpler for this situation, but doesn't scale well (in terms of code) to larger sizes.)

Change the "1" to "0" if you find you need the padding at the end instead of the start... or use Array.Resize in that case.

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冷默言语 2024-11-07 13:12:07

不完全确定其含义，但听起来您只是想要：

byte[] first = /* 3 bytes */
byte[] second = new byte[4];
// since 3 bytes, we'll do this manually; note second[0] is 0 already
second[1] = first[0];
second[2] = first[1];
second[3] = first[2];

当然，如果您实际上正在处理int，那么它已经左侧填充 0，至 4 个字节。

Not entirely sure of the meaning, but it sounds like you just want:

byte[] first = /* 3 bytes */
byte[] second = new byte[4];
// since 3 bytes, we'll do this manually; note second[0] is 0 already
second[1] = first[0];
second[2] = first[1];
second[3] = first[2];

Of course, if you are actually dealing with an int it is already padded on the left with 0, to 4 bytes.

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