VIM：如何避免替代中的替代？
我创建了一个函数来搜索自定义数量的空行（带或不带空格）并用新的（自定义）数量的空行替换它们。
fun! s:AddRemoveNumbEmptyLines()
if !exists("emptylinesbefore")
let emptylinesbefore = "How many empty lines do you search? \n (p.e. 2,3 4, ,3)"
endif
let b = inputdialog(emptylinesbefore)
if !exists("emptylinesafter")
let emptylinesafter = "How many empty lines must it be?"
endif
let c = inputdialog(emptylinesafter)
let m = repeat('\r', c)
exe 's/\(^\s*$\n\)\{'.b.'}/'.m.'/gc'
endfun
假设 b = 2，（2 或更多）AND m = 3
如果 vim 找到 4 个空行，它将替换为 3 个空行。
（没关系）。
但是，当我拒绝替换请求（我使用“c”（确认）标志）时，它在同一位置找到 3 个空行，并再次询问是否必须用 3 个空行替换。当我再次拒绝时，它在同一个地方找到了 2 个空行，并再次询问我是否要进行替换。
如何避免这些多个替换请求（在同一位置）？
希望我说清楚了:)
I created a function to search a custom number of empty lines (with or without spaces) and to replace them with a new (custom) number of empty lines.
fun! s:AddRemoveNumbEmptyLines()
if !exists("emptylinesbefore")
let emptylinesbefore = "How many empty lines do you search? \n (p.e. 2,3 4, ,3)"
endif
let b = inputdialog(emptylinesbefore)
if !exists("emptylinesafter")
let emptylinesafter = "How many empty lines must it be?"
endif
let c = inputdialog(emptylinesafter)
let m = repeat('\r', c)
exe 's/\(^\s*$\n\)\{'.b.'}/'.m.'/gc'
endfun
Let say b = 2, (2 and more) AND m = 3
If vim finds 4 empty lines it does a substitution to 3 empty lines.
(thats ok).
But when I refuse the substitution request (I use the "c" (confirm) flag) it finds at the same place 3 empty lines and asks again if it has to be replaced with 3 empty lines. When I refuse again, it finds at the same place, 2 empty lines and asks again if I want to do a substitution.
How can I avoid these multiple substitution requests (at the same place)?
Hope I made myself clear :)
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解决了！我只需检查前后行中是否有非空格 \S 。
resolved it! I just had to check for a non space \S in the line before and the line after.