jQuery Cookie 问题

发布于 2024-10-31 11:52:24 字数 1532 浏览 6 评论 0原文

我环顾四周，似乎找不到任何对我来说足够简单的东西...

我设置了一个网页来检测当前正在运行的浏览器，以及它是否是 Firefox 4.0 以外的浏览器，它会显示一个隐藏的 div，并发出警告，指出该页面最好在 Firefox 4.0 或更高版本中查看。该 div 中有一个按钮，可隐藏 div onclick。

我正在寻找一种方法来记住在会话期间已单击此按钮，以便当用户单击我的“主页”页面时，他们不会每次都收到相同的消息。

当前代码：

<head>
    <script src="js/browsercheck.js"></script>
    <script type="text/javascript">
        // external script "browsercheck.js" checks
        // which browser/version is being used
        // check browser and display message if != Firefox 4.0 or >
        function checkBrowser() {
            var browser = BrowserDetect.browser;
            var version = BrowserDetect.version;
            if (browser == "Firefox") {
                if (version >= 4) {
                    // do nothing
                }
            } else {
                document.getElementById("coverall").style.visibility="visible";
                document.getElementById("browser").innerHTML = browser + " " + version;
            } 
        }
        // remove overlay if user commands
        function removeCoverall() {
            document.getElementById("coverall").style.visibility="hidden";
        }
    </script>
</head>
<body>
    <div id="coverall" style="visibility:hidden;">
        <p>I see you're using <span id="browser"></span>. Please use Firefox.</p>
        <button type="button" onclick="removeCoverall()">I understand</button>
    </div>
</body>

原文

I've looked around a lot, and can't seem to find anything that's simple enough for me to do...

I've set up a web page that detects which browser is currently running, and if it's something other than Firefox 4.0, it displays a hidden div that gives a warning stating that the page is best viewed in Firefox 4.0 or greater. Within that div is a button that hides the div onclick.

I'm looking for a way to remember that this button has been clicked during a session, so that when a user clicks on my "home" page, they don't get the same message every time.

Current code:

<head>
    <script src="js/browsercheck.js"></script>
    <script type="text/javascript">
        // external script "browsercheck.js" checks
        // which browser/version is being used
        // check browser and display message if != Firefox 4.0 or >
        function checkBrowser() {
            var browser = BrowserDetect.browser;
            var version = BrowserDetect.version;
            if (browser == "Firefox") {
                if (version >= 4) {
                    // do nothing
                }
            } else {
                document.getElementById("coverall").style.visibility="visible";
                document.getElementById("browser").innerHTML = browser + " " + version;
            } 
        }
        // remove overlay if user commands
        function removeCoverall() {
            document.getElementById("coverall").style.visibility="hidden";
        }
    </script>
</head>
<body>
    <div id="coverall" style="visibility:hidden;">
        <p>I see you're using <span id="browser"></span>. Please use Firefox.</p>
        <button type="button" onclick="removeCoverall()">I understand</button>
    </div>
</body>

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泡沫很甜 2024-11-07 11:52:24

使用 jQuery 和 cookie 插件，您可以执行以下操作：

 function removeCoverall() {
            $.cookie("user_clicked_ok", "true");
            document.getElementById("coverall").style.visibility="hidden";
        }

$(window).ready(function() {
  if ($.cookie("user_clicked_ok")=="true") {removeCoverall();}
});

更多详细信息，请访问：http://www.electrictoolbox.com/jquery-cookies/

Using jQuery and the cookie plugin, you can do:

 function removeCoverall() {
            $.cookie("user_clicked_ok", "true");
            document.getElementById("coverall").style.visibility="hidden";
        }

$(window).ready(function() {
  if ($.cookie("user_clicked_ok")=="true") {removeCoverall();}
});

More details at: http://www.electrictoolbox.com/jquery-cookies/

回复收藏 0 原文

风情万种。 2024-11-07 11:52:24

在 removeCoverall 函数中，您可以设置一个 cookie 来指示用户关闭 div 并在 checkBrowser 函数中验证 cookie 是否存在，然后再显示 div。

回复收藏 0 原文

守望孤独 2024-11-07 11:52:24

You seem to have the right idea, you need cookies! YUM!

function removeCoverall() {
    var date = new Date();
    date.setTime(date.getTime()+(7*24*60*60*1000));// expires in one week
    document.cookie = 'skipNotify=1;expires='+date.toGMTString()+'; path=/';
    document.getElementById("coverall").style.visibility="hidden";
}

现在在 JavaScript 中检索 cookie 可能很困难，但您可以使用 PHP！

PHP

function checkBrowser() {
    <?php if(isset($_COOKIE['skipNotify']))echo'return;';?>
    var browser = BrowserDetect.browser;
    var version = BrowserDetect.version;
    if (browser == "Firefox") {
        if (version >= 4) {
            // do nothing
        }
    } else {
        document.getElementById("coverall").style.visibility="visible";
        document.getElementById("browser").innerHTML = browser + " " + version;
    } 
}

如果用户拥有 cookie，上面的代码会注入一个 return 语句，因此对该函数的调用不会执行任何操作。

正如其他帖子中提到的，我强烈建议您使用 jQuery 来满足您的所有 javascript 需求。它非常流行、稳定且有用！我只给出了我的答案，因为它不使用任何第三方解决方案。

You seem to have the right idea, you need cookies! YUM!

function removeCoverall() {
    var date = new Date();
    date.setTime(date.getTime()+(7*24*60*60*1000));// expires in one week
    document.cookie = 'skipNotify=1;expires='+date.toGMTString()+'; path=/';
    document.getElementById("coverall").style.visibility="hidden";
}

Now retrieving the cookie can be difficult in javascript, but you can use PHP!

PHP

function checkBrowser() {
    <?php if(isset($_COOKIE['skipNotify']))echo'return;';?>
    var browser = BrowserDetect.browser;
    var version = BrowserDetect.version;
    if (browser == "Firefox") {
        if (version >= 4) {
            // do nothing
        }
    } else {
        document.getElementById("coverall").style.visibility="visible";
        document.getElementById("browser").innerHTML = browser + " " + version;
    } 
}

The above code injects a return statement if the user has the cookie, so the call to the function won't do anything.

As mentioned in the other posts, I highly recommend you use jQuery for all your javascript needs. It's very popular, stable and useful! I only gave my answer as it does not use any third party solution.

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