类运算符之间的区别

发布于 2024-10-31 11:50:01 字数 213 浏览 1 评论 0原文

我正在阅读一点 C++，想知道是否有人可以向我解释一些类运算符的一些差异。有问题的运算符是：

* & 。 ->

我理解其中一些，但是，我看不出一些之间的区别。例如：

*x
&x
x.y
(*x).y
x -> y

有人可以举个例子并解释一下它们有何不同吗？

原文

I am reading into C++ a little bit and was wondering if someone could explain some differences of some of the class operators to me. The operators in question are:

* & . ->

I understand some of them, however, I fail to see the difference between some. For example:

*x
&x
x.y
(*x).y
x -> y

Can someone use an example and explain a bit how they would differ?

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青朷 2024-11-07 11:50:01

采用我的示例中给出的这个小结构：

struct MyStruct {
   int y;
};

*x 取消引用指针x。返回值是对x指向的对象的引用：

MyStruct* x = ...;
MyStruct xval = *x;
// or
MyStruct& xref = *x;
// read up on references to understand the latter

&x采用x的地址。因此，结果是一个指向 x 的指针。

MyStruct x;
MyStruct* pointer_to_x = &x;

xy 访问对象 x 中名为 y 的成员。

MyStruct x;
x.y = 5;
int a = x.y + 2;
// a==7

(*x).y 是第一个和第三个的组合：指针被取消引用，并且 . 运算符用于访问它的对象的成员指向.

a = (*pointer_to_x).y;

x->y 是（除非被邪恶的人覆盖）(*x).y 的快捷方式。

a = pointer_to_x->y;

Take this small structure as given for my samples:

struct MyStruct {
   int y;
};

*x dereferences the pointer x. The return value is a reference to the object pointed to by x:

MyStruct* x = ...;
MyStruct xval = *x;
// or
MyStruct& xref = *x;
// read up on references to understand the latter

&x takes the address of x. The result is therefore a pointer to x.

MyStruct x;
MyStruct* pointer_to_x = &x;

x.y accesses a member named y in the object x.

MyStruct x;
x.y = 5;
int a = x.y + 2;
// a==7

(*x).y is a combination of the first and the third: the pointer is dereferenced, and the .-operator is used to access a member of the object it points to.