underscore.js 解除绑定

Question

我很想解除绑定：

$("body").mousemove(_.bind(this.mousemove, this));

由于backbone.js和raphael.js之间的复杂混合，我需要通过underscore.js进行绑定：

var NodeView = Backbone.View.extend({

        dx: 0,
        dy: 0,

        click: function(event){
            alert('hello')
        },
        mousedown: function(event){
            this.dx = event.pageX - this.el.attr('x');
            this.dy = event.pageY - this.el.attr('y');
            this.el.attr({fill: "#0099FF"});

            $("body").mousemove(_.bind(this.mousemove, this));
        },
        mousemove: function(event){
            this.el.attr({  x: event.pageX - this.dx,
                            y: event.pageY - this.dy});
        },
        mouseup: function(event){
            this.el.attr({fill: "#EEEEEE"});
            $("body").mousemove(_.bind(this.mousenotmove, this));
        },

        render: function(){
            this.el = canvas.rect(this.model.get('xPos'), this.model.get('yPos'), 50, 50).attr({
                fill:   "#EEEEEE",
                stroke: "none",
                cursor: "move"
            });

            $(this.el.node).mousedown(_.bind(this.mousedown, this));
            $(this.el.node).mouseup(_.bind(this.mouseup, this));

            return this;
        }
    });

有什么建议吗？

Answer 1

感谢@Pointy（谢谢：D）：

解决方案很简单： $("body").unbind("mousemove");

请参阅第一篇文章中的评论。