删除具有相同列值的行

发布于 2024-10-31 03:36:00 字数 650 浏览 5 评论 0原文

我正在从邮政编码表中查询一堆城市。我只想通过独特的“城市”获取结果。（很多城市都有多个邮政编码。）这怎么办？

    $query = sprintf("SELECT `Zip`, `City`, `State`, `Lat`, `Long`, 
             ( 3959 * acos( cos( radians('%s') ) * cos( radians( `Lat` ) ) * 
             cos( radians( `Long` ) - radians('%s') ) +
             sin( radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance 
             FROM Zips HAVING distance < '%s' ORDER BY distance LIMIT 0 , 18",
      mysql_real_escape_string($lat),
      mysql_real_escape_string($lng),
      mysql_real_escape_string($lat),
      mysql_real_escape_string($radius));
    $result = mysql_query($query, $dbConn);

原文

I'm querying a bunch of cities from a zip-code table. I'd only like to grab results with an unique 'City'. (Lots of cities have multiple zips.) How could this be done?

    $query = sprintf("SELECT `Zip`, `City`, `State`, `Lat`, `Long`, 
             ( 3959 * acos( cos( radians('%s') ) * cos( radians( `Lat` ) ) * 
             cos( radians( `Long` ) - radians('%s') ) +
             sin( radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance 
             FROM Zips HAVING distance < '%s' ORDER BY distance LIMIT 0 , 18",
      mysql_real_escape_string($lat),
      mysql_real_escape_string($lng),
      mysql_real_escape_string($lat),
      mysql_real_escape_string($radius));
    $result = mysql_query($query, $dbConn);

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蓝戈者 2024-11-07 03:36:01

您在错误的地方使用了HAVING，这里需要WHERE，并使用GROUP BY按城市对结果进行分组

 $query = sprintf("SELECT `Zip`, `City`, `State`, `Lat`, `Long`, ( 3959 * acos( cos(
 radians('%s') ) * cos( radians( `Lat` ) ) * cos( radians( `Long` ) - radians('%s') ) + sin(
 radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance FROM Zips WHERE distance < '%s'  
 GROUP BY City ORDER BY distance LIMIT 0 , 18",

编辑

您也可以尝试

     $query = sprintf("SELECT `Zip`, `City`, `State`, `Lat`, `Long`, ( 3959 * acos( cos(
     radians('%s') ) * cos( radians( `Lat` ) ) * cos( radians( `Long` ) - radians('%s') ) + sin(
     radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance FROM Zips HAVING distance < '%s'  
     GROUP BY City  ORDER BY distance LIMIT 0 , 18";

或

$query = sprintf("SELECT * FROM (SELECT `Zip`, `City`, `State`, `Lat`, `Long`, ( 3959 * acos( cos(
     radians('%s') ) * cos( radians( `Lat` ) ) * cos( radians( `Long` ) - radians('%s') ) + sin(
     radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance FROM Zips HAVING distance < '%s'  
     ORDER BY distance LIMIT 0 , 18 ) as result_set GROUP BY City";

You are using HAVING at a wrong place WHERE is needed here and use GROUP BY to group result by city

 $query = sprintf("SELECT `Zip`, `City`, `State`, `Lat`, `Long`, ( 3959 * acos( cos(
 radians('%s') ) * cos( radians( `Lat` ) ) * cos( radians( `Long` ) - radians('%s') ) + sin(
 radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance FROM Zips WHERE distance < '%s'  
 GROUP BY City ORDER BY distance LIMIT 0 , 18",

EDIT

You could also try

     $query = sprintf("SELECT `Zip`, `City`, `State`, `Lat`, `Long`, ( 3959 * acos( cos(
     radians('%s') ) * cos( radians( `Lat` ) ) * cos( radians( `Long` ) - radians('%s') ) + sin(
     radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance FROM Zips HAVING distance < '%s'  
     GROUP BY City  ORDER BY distance LIMIT 0 , 18";

$query = sprintf("SELECT * FROM (SELECT `Zip`, `City`, `State`, `Lat`, `Long`, ( 3959 * acos( cos(
     radians('%s') ) * cos( radians( `Lat` ) ) * cos( radians( `Long` ) - radians('%s') ) + sin(
     radians('%s') ) * sin( radians( `Lat` ) ) ) ) AS distance FROM Zips HAVING distance < '%s'  
     ORDER BY distance LIMIT 0 , 18 ) as result_set GROUP BY City";

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