Java 位操作 - (num >>= 1) 的作用是什么？
我正在查看一些将数字输出为带有前缀 0 的二进制形式的代码。
byte number = 48;
int i = 256; //max number * 2
while( (i >>= 1) > 0) {
System.out.print(((number & i) != 0 ? "1" : "0"));
}
并且不明白 i >>= 1 的作用。我知道i >>> 1 向右移动 1 位，但不明白 = 的作用，据我所知，不可能搜索“>>=” ” 来了解它的含义。
I was looking at some code that outputs a number to the binary form with prepended 0s.
byte number = 48;
int i = 256; //max number * 2
while( (i >>= 1) > 0) {
System.out.print(((number & i) != 0 ? "1" : "0"));
}
and didn't understand what the i >>= 1 does. I know that i >> 1 shifts to the right by 1 bit but didn't understand what the = does and as far as I know, it is not possible to do a search for ">>=" to find out what it means.
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i >>= 1只是i = i >>> 的简写形式。 1与i += 4是i = i + 4的缩写编辑：具体来说，这些都是 复合赋值运算符。
i >>= 1is just shorhand fori = i >> 1in the same way thati += 4is short fori = i + 4EDIT: Specifically, those are both examples of compound assignment operators.