Simulink中Matlab函数无法输出多维矩阵
例如，我有创建矩阵 2x2 的函数：[1 2; 3 4] 我有这样简单的函数：
function[result] = Rho(x)
// I've tried and so:
result = [1 2; 3 4];
// And so:
result(1,1) = 1;
result(1,2) = 2;
result(2,1) = 3;
result(2,2) = 4;
在Matlab窗口中我看到正确的结果：
>> Rho(1)
ans =
1 2
3 4
但在Simulink中我总是得到[1;2;3;4]。我的错误在哪里？
PS 我忘记删除函数的参数 x，因为在实际函数中我根据参数 x 制作矩阵。但它在我们的例子中不起作用
For example I have function that creates matrix 2x2 : [1 2; 3 4]
I have such simple function:
function[result] = Rho(x)
// I've tried and so:
result = [1 2; 3 4];
// And so:
result(1,1) = 1;
result(1,2) = 2;
result(2,1) = 3;
result(2,2) = 4;
In Matlab window i see right result:
>> Rho(1)
ans =
1 2
3 4
But in Simulink I always get [1;2;3;4]. Where is my mistake?
P.S. I forgot to remove argument x of function, because in real function I make matrix depending on argument x. But it doesn't play role in our example
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您遇到的问题可能是由于 MATLAB Function 模块 的参数设置（现在称为 新版本中解释的 MATLAB Function 块）。查看该块的参数对话框：
请注意，您需要设置 输出维度为 2，并取消选中将二维结果折叠为一维复选框。如果选中此选项，则通过从左到右提取每列的值，您的 2×2 矩阵将转换为一维数组，最终为
[1 3 2 4]在你的例子中。应用上述更改后，您所要做的就是调整 < 的大小strong>显示块，以便它显示 2 行和 2 列。
The problem you are having is likely due to the parameter settings for your MATLAB Function block (now called an Interpreted MATLAB Function block in newer versions). Take a look at the Parameters Dialog Box for that block:
Note that you will want to set the Output dimensions to 2 and uncheck the Collapse 2-D results to 1-D check box. If this is left checked, then your 2-by-2 matrix will be turned into a 1-D array by extracting values along each column from left to right, which ends up being
[1 3 2 4]in your example.Once you apply the above changes, then all you should have to do is resize your Display block so that it shows your 2 rows and 2 columns.