在C中初始化结构体中的数组

发布于 2024-10-30 14:30:46 字数 226 浏览 4 评论 0原文

struct myStruct
{   
    short int myarr[1000];//want to initialize all elements to 0
}

如何初始化数组？

我尝试在结构内执行 short int* myarr[1000]={0} 但这是错误的。我该怎么做？我不介意在实现文件中这样做。该结构包含在头文件中。

原文

struct myStruct
{   
    short int myarr[1000];//want to initialize all elements to 0
}

How do I initialize the array?

I tried doing short int* myarr[1000]={0} inside the struct but it's wrong. How can I do this? I don't mind doing it in the implementation file. This struct is contained in a header file.

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

彡翼 2024-11-06 14:30:46

使用通用初始值设定项：{0}。

通用初始化器适用于任何东西，并将元素初始化为正确的 0（对于指针，NULL，对于整数，0，对于双精度数，0.0，.. .)：

struct myStruct example1 = {0};
struct myStruct example2[42] = {0};
struct myStruct *example3 = {0};

编辑动态分配的对象。

如果您要动态分配内存，请使用 calloc 而不是 malloc。

p = malloc(nelems * sizeof *p); /* uninitialized objects; p[2] is indeterminate */
q = calloc(nelems, sizeof *q);  /* initialized to zero; q[2] is all zeros */

对于 realloc（以及可能的其他情况），您需要 memset。

Use the universal initializer: {0}.

The universal initializer works for anything and initializes the elements to the proper 0 (NULL for pointers, 0 for ints, 0.0 for doubles, ...):

struct myStruct example1 = {0};
struct myStruct example2[42] = {0};
struct myStruct *example3 = {0};

Edit for dynamically allocated objects.

If you're allocating memory dynamically use calloc rather than malloc.

p = malloc(nelems * sizeof *p); /* uninitialized objects; p[2] is indeterminate */
q = calloc(nelems, sizeof *q);  /* initialized to zero; q[2] is all zeros */

With realloc (and possibly other situations) you need to memset.

回复收藏 0 原文