重新启动游戏并重新实例化对象

发布于 2024-10-30 07:56:02 字数 456 浏览 1 评论 0原文

简介

我正在用 C++ 创建一个小游戏，想创建一个重新启动游戏的函数。

首先，我创建对象player。然后我有一个 if 语句来确定何时按下某个键来调用 New() 方法。

我的目标

在该方法中，我想重新实例化 Player 类的对象，因此所有变量都将被重置。

我的代码：

Player player;

//New game method
Game::New()
{
    player = new Player();
}

//Game loop
Game::Loop()
{
    if(keyispressed(key))
    {
        Game.New();
    }
}

有什么建议吗？

原文

Introduction

I am creating a small game in C++ and would like to create a function to restart the game.

First I am creating the object player. Then I have an if statement to determine when a certain key is pressed to call the New() method.

My goal

In that method I would like to reinstantiate an object of the Player class, so all variables will be resetted.

My code:

Player player;

//New game method
Game::New()
{
    player = new Player();
}

//Game loop
Game::Loop()
{
    if(keyispressed(key))
    {
        Game.New();
    }
}

Any suggestions?

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累赘 2024-11-06 07:56:02

您混淆了指针变量和非指针变量。 new Player() 返回动态分配的 Player 对象的地址。您不能将此地址分配给非指针变量player；您需要将 player 声明为指针：

Player* player = new Player();

您还需要记住释放之前使用匹配的 delete 分配的内存：

// player starts out pointing to nothing
Player* player = 0;

//New game method
Game::New()
{
    // If player already points to something, release that memory
    if (player)
        delete player;

    player = new Player();
}

现在 player > 是一个指针，您必须更新您编写的使用播放器的任何其他代码，才能使用 -> 成员访问运算符。例如，player.name() 将变为 player->name()

You're confusing pointer and non-pointer variables. new Player() returns the address of a dynamically allocated Player object. You cannot assign this address to the non-pointer variable player; you'd need to declare player as a pointer:

Player* player = new Player();

You also need to remember to release the memory previously allocated with a matching delete:

// player starts out pointing to nothing
Player* player = 0;

//New game method
Game::New()
{
    // If player already points to something, release that memory
    if (player)
        delete player;

    player = new Player();
}

Now that player is a pointer you'll have to update any other code you've written which uses player, to use the -> member access operator. For example, player.name() will become player->name()

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