编写运算符方法的实现
所以我有一个 LongInt 类，它将为 + 和 * 运算符提供新的定义。头文件中的初始化如下所示：
friend LongInt operator+(const LongInt& x, const LongInt& y);
friend LongInt operator*(const LongInt& x, const LongInt& y);
但是，在我的实现文件中，我定义了标头中找到的方法，VS 无法识别标头中列出的operator+ 函数或operator* 函数。我正在使用代码：
friend LongInt LongInt::operator+(const LongInt& x, const LongInt& y)
{
}
并且
friend LongInt LongInt::operator*(const LongInt& x, const LongInt& y)
{
}
当我尝试定义运算符时，关于为什么此代码不起作用的任何想法？
So I have a LongInt class that will have new definition for the + and * operators. The initialization in the header file looks like:
friend LongInt operator+(const LongInt& x, const LongInt& y);
friend LongInt operator*(const LongInt& x, const LongInt& y);
however in my implementation file, where I'm defining the methods found in the header, VS doesn't recognize the operator+ function or the operator* function as being listed in the header. I'm using the code:
friend LongInt LongInt::operator+(const LongInt& x, const LongInt& y)
{
}
and
friend LongInt LongInt::operator*(const LongInt& x, const LongInt& y)
{
}
Any ideas as to why this code wont work when I'm trying to define the operators?
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friend关键字仅在类内部声明或定义运算符时使用；当在类内部将运算符声明为friend并在其他地方定义它时，friend仅用于声明，而不用于定义。此外，在类中声明为friend的函数实际上是命名空间范围内的自由函数，而不是类成员。因此，您的定义应该看起来更像是：如需进一步阅读材料，请阅读以下页面：C++ 常见问题解答：朋友< /a>
The
friendkeyword is only used when declaring or defining the operator inside of a class; when declaring the operator as afriendinside of the class and defining it elsewhere,friendis only used on the declaration, not the definition. Also, functions declared asfriendinside a class are in fact free functions in namespace scope, not class members. So, your definitions should look more like:For further reading material, read over the following page: C++ FAQ: Friends
您正在重写运算符...您使用运算符“调用”它：
You're overriding an operator ... you "call" it using the operator: