下载生成的 HTML 文件
我有一个生成的 HTML 文件，我需要能够通过单击按钮来下载该文件（因此不会在新窗口中打开，仅显示此特定 html 文件的保存文件对话框）。
到目前为止我拥有的代码：
AVaadinApplication application = VaadinContext.getCurrentInstance().getVariable(VaadinContext.APPLICATION, AVaadinApplication.class);
StreamResource inputHTML = new StreamResource(
new StreamResource.StreamSource() {
private static final long serialVersionUID = 1L;
@Override
public InputStream getStream() {
return new ByteArrayInputStream(getHelpContentString(getLocale()).getBytes());
}
}, "help_" + getLocale() + ".html", application);
inputHTML.setCacheTime(0);
非常感谢任何帮助，因为我对此一直很头疼。
I have a generated HTML file which I need to be able to download at the click of a button (so not opening in a new window, just showing the save file dialog for this particular html file).
The code I have so far:
AVaadinApplication application = VaadinContext.getCurrentInstance().getVariable(VaadinContext.APPLICATION, AVaadinApplication.class);
StreamResource inputHTML = new StreamResource(
new StreamResource.StreamSource() {
private static final long serialVersionUID = 1L;
@Override
public InputStream getStream() {
return new ByteArrayInputStream(getHelpContentString(getLocale()).getBytes());
}
}, "help_" + getLocale() + ".html", application);
inputHTML.setCacheTime(0);
Any help is greatly appreciated as I've been breaking my head on this.
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将 HTML 封装在 Zip 文件中。据我所知，没有浏览器会尝试显示 Zip 文件，而是将其作为文件推出以“打开（在 Zip 存档程序中）或保存”。
Wrap the HTML in a Zip file. No browser I know will attempt to display a Zip file, but instead push it out as a file to 'Open (in a Zip archive program) or Save'.
您应该将结果的 HTTP
Content-Disposition标头设置为附件。如何执行此操作取决于您与 Web 服务器交互的方式。以前的代码是否作为 servlet、游戏框架、cgi 等运行？You should set the HTTP
Content-Dispositionheader of the result to attachment. How you do that depends on how you interact with the web server. Are yore code running as a servlet, in the play framwork, as a cgi, etc?