从当前目录创建 RPM
我正在尝试从本地源创建 rpm。是否可以像 pdebuild 那样进行编译 - 只需将本地目录复制为源并对该副本进行操作？每次我执行 rpmbuild -ba ... 时，它都会尝试解压 RPMBUILD/SOURCE 中的一些存档，但我不想那样做。
本质上，我希望能够使用代码签出存储库，在该签出目录中执行 rpmbuild -ba application.spec 并让它做正确的事情......这可能吗？
I'm trying to create an rpm from local source. Is it possible to do compilation in a similar to what pdebuild does - just copy the local directory as the source and operate on that copy? Every time I do rpmbuild -ba ... it tries to unpack some archive in RPMBUILD/SOURCE, but I don't want to go that way.
Essentially I'd like to be able to just checkout the repository with the code, do rpmbuild -ba application.spec in that checkout directory and have it do the right thing... Is that possible?
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我不知道比以下更好的方法：
对于我自己的项目，我总是使用
Makefile定义一次make rpm，然后使用它。I don't know about a better way than the following:
For my own project, I'm always using a
Makefileto definemake rpmonce and then just use it.规范文件中的
%setup宏用于解压源代码。删除它，你的问题就消失了，你可以做任何你想做的事情来获取源代码。The
%setupmacro in the spec file is what unpacks the source. Remove that, and your problem goes away, and you can do anything you'd like to fetch the source.