Grails JSONBuilder
如果我有一个简单的对象,例如
class Person {
String name
Integer age
}
我可以使用 JSONBuilder 轻松地将其用户定义的属性呈现为 JSON,
def person = new Person(name: 'bob', age: 22)
def builder = new JSONBuilder.build {
person.properties.each {propName, propValue ->
if (!['class', 'metaClass'].contains(propName)) {
// It seems "propName = propValue" doesn't work when propName is dynamic so we need to
// set the property on the builder using this syntax instead
setProperty(propName, propValue)
}
}
def json = builder.toString()
当属性很简单(即数字或字符串)时,这可以正常工作。但是,对于更复杂的对象,例如
class ComplexPerson {
Name name
Integer age
Address address
}
class Name {
String first
String second
}
class Address {
Integer houseNumber
String streetName
String country
}
是否有一种方法可以遍历整个对象图,将适当的嵌套级别的每个用户定义的属性添加到 JSONBuilder?
换句话说,对于 ComplexPerson
的实例,我希望输出为
{
name: {
first: 'john',
second: 'doe'
},
age: 20,
address: {
houseNumber: 123,
streetName: 'Evergreen Terrace',
country: 'Iraq'
}
}
Update
我不认为我可以使用 Grails JSON 转换器来执行此操作,因为我返回的实际 JSON 结构看起来像是这样请
{ status: false,
message: "some message",
object: // JSON for person goes here
}
注意:
- 为
ComplexPerson
生成的 JSON 是较大 JSON 对象的元素, - 我想排除某些属性,例如
metaClass
和class
到
如果可以将 JSON 转换器的输出作为对象获取,我可以对其进行迭代并删除 metaClass
和 class
属性,然后将其添加 外部 JSON 对象。
然而,据我所知,JSON 转换器似乎只提供“全有或全无”的方法,并将其输出作为字符串返回
If I have a simple object such as
class Person {
String name
Integer age
}
I can easily render it's user-defined properties as JSON using the JSONBuilder
def person = new Person(name: 'bob', age: 22)
def builder = new JSONBuilder.build {
person.properties.each {propName, propValue ->
if (!['class', 'metaClass'].contains(propName)) {
// It seems "propName = propValue" doesn't work when propName is dynamic so we need to
// set the property on the builder using this syntax instead
setProperty(propName, propValue)
}
}
def json = builder.toString()
This works fine when the properties are simple, i.e. numbers or strings. However for a more complex object such as
class ComplexPerson {
Name name
Integer age
Address address
}
class Name {
String first
String second
}
class Address {
Integer houseNumber
String streetName
String country
}
Is there a way that I can walk the entire object graph, adding each user-defined property at the appropriate nesting level to the JSONBuilder?
In other words, for an instance of ComplexPerson
I would like the output to be
{
name: {
first: 'john',
second: 'doe'
},
age: 20,
address: {
houseNumber: 123,
streetName: 'Evergreen Terrace',
country: 'Iraq'
}
}
Update
I don't think I can use the Grails JSON converter to do this because the actual JSON structure I'm returning looks something like
{ status: false,
message: "some message",
object: // JSON for person goes here
}
Notice that:
- The JSON generated for the
ComplexPerson
is an element of a larger JSON object - I want to exclude certain properties such as
metaClass
andclass
from the JSON conversion
If it's possible to get the output of the JSON converter as an object, I could iterate over that and remove the metaClass
and class
properties, then add it to the outer JSON object.
However, as far as I can tell, the JSON converter only seems to offer an "all or nothing" approach and returns it output as a String
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我终于弄清楚如何使用
JSONBuilder
来做到这一点,这是代码您可以通过将上面的代码以及以下代码粘贴到 grails 控制台中来测试
它它应该生成以下输出将
Complex
的序列化实例存储为object
属性的值:I finally figured out how to do this using a
JSONBuilder
, here's the codeYou can test this by pasting the code above along with the following into the grails console
It should generate the following output which stores the serialized instance of
Complex
as the value of theobject
property:为了让转换器转换整个对象结构,您需要在配置中设置一个属性来指示这一点,否则它将只包含子对象的 ID,因此您需要添加以下内容:
有关更多信息,请转到 Grails 转换器参考。
然而,就像您在上面的评论中提到的那样,它要么全有,要么全无,所以您可以做的是为您的班级创建自己的编组器。我之前必须这样做,因为我需要包含一些非常具体的属性,所以我所做的是创建一个扩展 org.codehaus.groovy.grails.web.converters.marshaller.json.DomainClassMarshaller 的类。类似于:
上面的代码与 DomainClassMarshaller 的代码几乎相同,其想法是您添加或删除您需要的内容。
然后,为了让 Grails 使用这个新的转换器,您需要将其注册到 resources.groovy 文件中,如下所示:
正如您所看到的,这个编组器适用于特定的类,因此,如果您想要更通用,您可以要做的就是创建一个超类并让您的类继承该超类,因此在 support 方法中您所做的就是说此编组器支持作为该超类实例的所有类。
我的建议是查看转换器的 grails 代码,这将使您了解它们内部如何工作,以及如何扩展它,使其按照您需要的方式工作。
这篇 Nabble 中的帖子也可能有帮助。
另外,如果您也需要对 XML 执行此操作,那么您只需扩展类 org.codehaus.groovy.grails.web.converters.marshaller.xml.DomainClassMarshaller 并按照相同的过程进行注册,等等。
In order for the converter to convert the whole object structure you need to set a property in the config to indicate that, otherwise it will just include the ID of the child object, so you need to add this:
For more information go Grails Converters Reference.
However, like you mentioned it in the comment above it is all or nothing, so what you can do is create your own marshaller for your class. I had to do this before because I needed to include some very specific properties, so what I did was that I created a class that extends org.codehaus.groovy.grails.web.converters.marshaller.json.DomainClassMarshaller. Something like:
That code above is pretty much the same code as it is DomainClassMarshaller, the idea would be that you add or remove what you need.
Then in order for Grails to use this new converter what you need is to register it in the resources.groovy file, like this:
As you can see this marshaller works for a specific class, so if you want to make more generic what you can do is create a super class and make your classes inherit from that so in the support method what you do is say this marshaller support all the classes that are instances of that super class.
My suggestion is to review the grails code for the converters, that will give you an idea of how they work internally and then how you can extend it so it works the way you need.
This other post in Nabble might be of help too.
Also, if you need to do it for XML as well then you just extend the class org.codehaus.groovy.grails.web.converters.marshaller.xml.DomainClassMarshaller and follow the same process to register it, etc.